Question

( t^15/27x^9 ) ^-2/3 Please solve this it is fraction with a negative fraction exponent

Answer 1

Answer:

Step-by-step explanation:

Exponent laws:

$(a^{m})^{n}=a^{m*n}\\\\a^{-m}=\frac{1}{a^{m}}$

$(t^{\frac{15}{27}}x^{9}})^{\frac{-2}{3}}= \ t^{\frac{15}{27}*\frac{-2}{3}}*x^{9*\frac{-2}{3}}\\\\\\= t^{\frac{5}{9}*\frac{-2}{3}}*x^{3*-2}\\\\=t^{\frac{-10}{27}}x^{-6}\\\\=\frac{1}{t^{\frac{10}{27}}x^{6}}$