Question

Write the expression in complete factored form. (B+3)-c(b+3)

Answer 1

(B+3)-c(b+3)
Simplifying
(B + 3) + -1c(b + 3)

Reorder the terms:
(3 + B) + -1c(b + 3)

Remove parenthesis around (3 + B)
3 + B + -1c(b + 3)

Reorder the terms:
3 + B + -1c(3 + b)
3 + B + (3 * -1c + b * -1c)

Reorder the terms:
3 + B + (-1bc + -3c)
3 + B + (-1bc + -3c)

Final result:
3 + B + -1bc + -3c

Answer 2

ANSWER

$(b + 3)(1 - c)$

EXPLANATION

The given expression is:

$(b + 3) - c(b + 3)$

We can rewrite this to reveal the invisible 1 multiplying the first term.

$1(b + 3) - c(b + 3)$

There is a common factor of (b+3).

We factor to get;

$(b + 3)(1 - c)$

Therefore the completely factored form of the given expression is

$(b + 3)(1 - c)$