Find the number of sides of a regular polygon if the sum of its interior angle is 1440

1 answer:

8 0

The formula is 180(n-2)= 1140 then you divide 1140 by 180 to get 8 so then it would like like n-2=8 add the 2 over and n (being the number of sides)= 10 so your answer will be 10

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(12f^2-9f+15)-(-4f^2-3f+6) subtract.

german

So what you do is distribute the invisible -1 in front of the second parenthasees set and add like terms
remember
x^2+3x^2=4x^2
-(3+4x-x^2)=-1(3x+4x-x^2)=-3-4x+x^2

so first distribute the negative 1
-1(-4f^2-3f+6)=4f^2+3f-6
add
12f^2-9f+15+4f+3f-6
group like terms
12f^2+4f^2-9f+3f+15-6
add
16f^2-6f+9

aswer is 16f^2-6f+9

8 0

3 years ago

How would you solve this? Please give an explanation.

Neporo4naja [7]

The first three elements of the recursive series are 6, 10, 8. (Correct choice: B)

<h3>How to generate values from a recursive function</h3>

In this question we have a kind of recursive function known as Fibonacci's function, where a value of the series is generated from at least immediately previous elements. In this case, we need to find the first three elements from the fifth and fourth elements of the series:

$a_{n-2} = a_{n-1} - a_{n} + 4$