4-3<9
5-3<9
6-3<9
and so on...
Let a=price of adult ticket
let c=price of a child's ticket
start out by writing the following system of equations:
3a+4c=132
2a+3c=94
then, multiply the first equation by 2, and the second equation by 3 to get the following system of equations:
6a+8c=264
6a+9c=282
subtract the like terms to get the following equation:
-c=-18
divide both sides by -1 to get rid of the negative to get the price of a child's ticket to be $18. to find the price of an adult ticket, pick one of the original equations to substitute the 18 in for c to find a. for example:
2a+3c=94
2a+3(18)=94
2a+54=94
-54 -54
2a=40
2 2
a=20
or if you decide to use the other equation:
3a+4c=132
3a+4(18)=132
3a+72=132
-72 -72
3a=60
3 3
a=20
either way, you still get an adults ticket to be $20 and a child's ticket to be $18.
B= y-intercept
b= 4
m= slope
m= 1/2
y=1/2x+4
Answer: A. 12, 12, 36
I hope this helps you
Answer:
Option 3 is right
Step-by-step explanation:
-2/3 = -.66
-3/5 = -.60
-1/2 = -.50
5/8 = .625
