Obtuse quadrilaateral. midpoint(-1,3) with slooe 1/2
distance 2
Area of sector is 17.584 meters
<em><u>Solution:</u></em>
Given that we have to find the approximate area of a sector given O= 56 degrees with a diameter of 12m
Diameter = 12 m
Radius = Diameter / 2 = 6 m
An angle of 56 degrees is the fraction
of the whole rotation
A sector of a circle with a sector angle of 56 degrees is therefore also the fraction
of the circle
The area of the sector will therefore also be
of the area

Thus area of sector is 17.584 meters
Answer:
The equation of the regression line for the following data is:
y=2.4x+120.1
Step-by-step explanation:
We are given a set of data values in table form as:
Day(x) Number of visitors(y)
1 120
2 124
3 130
4 131
5 135
6 132
7 135
Hence, when we draw a scatter plot with the help of these data points using the linear regression calculator we see that the regression line is a line with y-intercept as (0,120.1) and x-intercept as (-50.04,0)
Hence, the regression line for the following data is:
y=2.4x+120.1
*See diagram in the attachment
Answer:
27 inches
Step-by-step explanation:
Combined perimeter = perimeter of rectangle + perimeter of triangle = 63 inches
Perimeter of rectangle = 2(L + W)
L = 11 in.
W = 7 in.
Perimeter of rectangle = 2(11 + 7) = 36 in.
Let perimeter of the triangle be represented by x
Therefore:
36 + x = 63
Subtract 36 from each side
x = 63 - 36
x = 27
Perimeter of triangle = 27 inches
Answer:
Step-by-step explanation:
You turn 5 3/5 into an improper fraction, to do that you do 5 x 5 = 25 then 25 + 3 = 28/5
so in a 7 day period she swims 5.6 kilometers. So you have to do 5.6/7 = 0.8
So it would be 0.8 kilometers in a day which is 4/5 kilometers so I don't know if the answers were just wrong?