Question

I need help finding the distince.​

Answer 1

Answer:

guessing that the area of the inner rectangle is 10m²

and the other rectangle is 16m*10m= 160m²

we can say that

(16-x) * (10-x) = 10

for the area of the inner rectangle

let's calculate the lefthand side of the equation

160 - 16x -10x + x² = 10

160 -26x +x² = 10

subtract 10 on both sides

150 -26x +x² = 0

rearrange

x² -26x + 150 = 0

looks like something we can throw the pq formula on to solve for x

with p = -26 and q = 150

$x = - \frac{ - 26}{2} \frac{ + }{ - } \sqrt{( \frac{ - 26}{2})^{2} - 150 }$

$x = 13 \frac{ + }{ - } \sqrt{169 - 150 }$

$x = 13 \frac{ + }{ - } \sqrt{19 }$

$x1 = 8.64$

$x2 =17.36$

we need to interpret this solutions

but to be sure on this, I need the unreadable text of the photographed problem