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Aleks [24]
3 years ago
8

Answer the picture please

Mathematics
1 answer:
Irina18 [472]3 years ago
8 0

Answer:

42 miles ≈ 68 km

35 km ≈ 22 miles

150 miles ≈ 252 km

Step-by-step explanation:

1 mile ≈ 1.6 km - just look at the picture

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Step-by-step explanation:

A = -7.

B = -8 x-(-6) is the same as x + 6

C = 13

D = 2

E = -3

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Which multiplication properties is 1/5•5
allsm [11]

See picture for solution to your problem.

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△klm, lm=20 sqrt 3 m∠k=105°, m∠m=30° find: kl and km
Anarel [89]

Answer:

KL =  \frac{20\sqrt{6}}{1+\sqrt{3}} = 17.93

MK =  \frac{40\sqrt{3}}{1+\sqrt{3}} = 25.36


Explanation:

According to the Law of Sines:

\frac{a}{sinA}=\frac{b}{sinB}= \frac{c}{sinC}

where:

A, B, and C are angles

a, b, and c are the sides opposite to the angles


First of all, let's find m∠L: the sum of the angles of a triangle is 180°, therefore

m∠K + m∠L + m∠M = 180°

m∠L = 180° - m∠K - m∠M

m∠L = 180° - 105° - 30°

m∠L = 45°


Now, we can apply the Law of Sines to our case (see picture attached):

\frac{LM}{sinK}=\frac{MK}{sinL}=\frac{KL}{sinM}


Let's solve one side at the time:

\frac{LM}{sinK}=\frac{MK}{sinL}

\frac{20\sqrt{3}}{sin(105)}=\frac{MK}{sin(45)}

MK = \frac{20\sqrt{3} }{sin(105)} \cdot sin(45)

MK = \frac{40\sqrt{3} }{1+\sqrt{3} } = 25.36


Similarily:

\frac{LM}{sinK}=\frac{KL}{sinM}

\frac{20\sqrt{3}}{sin(105)}=\frac{KL}{sin(30)}

KL = \frac{20\sqrt{3} }{sin(105)} \cdot sin(30)

KL = \frac{20\sqrt{6}}{1+\sqrt{3}} = 17.93

8 0
3 years ago
If A=Jame’s present age , write an expression for his age seven years from now
yan [13]

the answer for your question is, A+7

3 0
3 years ago
Read 2 more answers
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