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vladimir2022 [97]
3 years ago
6

Help with Probability!!

Mathematics
2 answers:
NNADVOKAT [17]3 years ago
8 0
Based on Jude's results, the experimental probability of landing on blue is 24%
damaskus [11]3 years ago
4 0
As the blue landed 6 times the experimental Probability = 6/25
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(Will award 15 pts.)
Degger [83]
13 hearts are in a deck of cards, and we are picking with replacement so

P(HH)=(1/4)(1/4)=(1/4)^2=1/16
3 0
4 years ago
A cylinder has a volume of 225π inches 3 . What is its height, if its radius is 10 inches?
masya89 [10]
V=(225pi) in
r=(10in)
h=?

v=r2hpi
h=2,25in
4 0
4 years ago
I need help with these two trigonometry problems.
Sloan [31]

Answer:

B \approx 32.1\°; A \approx 39.0\°

Step-by-step explanation:

Sine theorem: in any triangle, the ratio between a side and the sine of the opposite angle is constant

\frac{sin\ \alpha}a = \frac{sin\ \beta}b =\frac{sin\ \gamma}c

In our case, for the left triangle,

\frac {sin\ 103\°}{11} =\frac{sin\ B} 6 \rightarrow sin\ B = \frac6{11} sin\ 103\°

Time to grab a calculator and crunch numbers. Double check your calculator is in degrees and not in radians (plug in sin 30°, if you're getting 0.5 you're good) and you will get

sin\ B \approx 0.53 \rightarrow B \approx 32.1\°

Same difference with the right triangle. With the same calculations

sin\ A = \frac{26}{41} sin 83\° \approx 0.68 \rightarrow A \approx 39.0\°

5 0
2 years ago
|x^2+x-1|=1 solve for x
Marizza181 [45]

<span><span>x=<span>−3</span></span><span>x=<span>-3</span></span></span>

Here the steps

<span><span><span>2<span>x+1</span></span>−<span>1<span>x−1</span></span>=<span><span>2x</span><span><span>x2</span>−1</span></span></span><span><span>2<span>x+1</span></span>-<span>1<span>x-1</span></span>=<span><span>2x</span><span><span>x2</span>-1</span></span></span></span>

 <span>x<span>−3</span></span><span><span>(<span>x+1</span>)</span><span>(<span>x<span>−1</span></span>)</span></span>=<span><span>2x</span><span><span>(<span>x+1</span>)</span><span>(<span>x<span>−1</span></span>)</span></span></span><span><span><span>x<span>-3</span></span><span><span>x+1</span><span>x<span>-1</span></span></span></span>=<span><span>2x</span><span><span>x+1</span><span>x<span>-1</span></span></span></span></span>

<span><span><span>(<span>x+1</span>)</span><span>(<span>x<span>−1</span></span>)</span></span><span><span>x+1</span><span>x<span>-1</span></span></span></span>

<span><span><span>x<span>−3</span></span>=<span>2x</span></span><span><span>x<span>-3</span></span>=<span>2x</span></span></span>

<span><span>x=<span>−3</span></span><span>x=<span>-<span>3</span></span></span></span>

<span><span><span><span>So the answer comes out to be x = 3 I hope this was helpful </span></span></span></span>

3 0
4 years ago
HELP PLEASE ANYONE STEP BY STEP TIMED
UNO [17]

Answer:

\huge\boxed{\text{B) 4}}

Step-by-step explanation:

We can use the properties of some of these circles to solve and find the value of x.

FIrst off - we know that to find the side of a right triangle we can use the Pythagorean Theorem, which states that a^2 + b^2 = c^2 (a and b being legs, c being the hypotenuse.)

<h2><u>Finding the hypotenuse</u></h2>

We also know that this triangle is in a circle. Part of the hypotenuse and the altitude of the triangle are in the circle.

Point W is the center of the circle. Therefore, any points stretching to the edge from it will be equal (since this is a circle).

With this knowledge - UW and WZ are equal.

Therefore, since UW is x-1, WZ will be too.

We also know the length of VZ. We can add this to WZ to find the length of the whole hypotenuse.

\displaystyle x-1+2 \\ x+1

So the length of the hypotenuse, WV, is x+1.

<h2><u>Finding the value of x</u></h2>

Now that we know the length of the hypotenuse, we can use the Pythagorean Theorem like we stated before to find the value of x.

We know the two legs are x-1 and 2x-4, while the hypotenuse is

  • \displaystyle (x-1)^2 + (2x-4)^2 = (x+1)^2
  • (x^2 - 2x + 1) + (4x^2-16x+16) = (x^2 + 2x + 1) (use FOIL to find the value of each expression squared)
  • 5x^2 - 18x + 17 = x^2 + 2x + 1 (simplify the left side)
  • 4x^2 -20x + 16 = 0 (subtract both sides by x^2 +2x + 1)
  • x = \frac{{ -b \pm \sqrt {b^2 - 4ac} }}{{2a}} (Quadratic formula)
  • \frac{{ -(-20) \pm \sqrt {(-20)^2 - 4 \cdot 4 \cdot 16} }}{{2 \cdot 4}} (plug in values from equation)
  • \frac{{ 20 \pm \sqrt {400 - 256} }}{8}} (simplify)
  • \frac{{ 20 \pm \sqrt {144} }}{8}} (simplify)
  • \frac{{ 20 \pm 12 }}{8}} (simplify)
  • \displaystyle x = \frac{20+12}{8} \ \text{and} \ \frac{20-12}{8} (use plus/minus to find two roots)
  • \displaystyle x = \frac{32}{8} \ \text{and} \ \frac{8}{8} (simplify)
  • \displaystyle x = 4 \ \text{and} \ 1

1 can not be a possible answer because UW would end up being (1-1) = 0 units long! This isn't possible!

Therefore, the correct answer would be B) 4.

Hope this helped!

6 0
3 years ago
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