Question

In ten-pin bowling, the highest possible score in a single game is 300.

Answer 1

Answer:

a) Is it possible for Fred to accomplish this? Yes

b) If it is possible, what score does he need in his next game? 293

Step-by-step explanation:

Step 1

Let us represent the number of games Fred bowled to get an average of 177 = X

His total points scored in that game would be

177 × X

= 177X

To achieve an average of 178 for his next game,

The total number of points he scored was 199, hence that is represented as:

178 = 177X + 199/ X + 1

178(X + 1) = 177X + 199

178X + 178 = 177X + 199

178X - 177X = 199 - 178

X = 21

Hence, Fred bowled 21 games to achieve an average of 178

Therefore, the score he needs to have on the 23rd game is obtained as:

= (23 × 183) - (22 × 178) = 4209 - 3916 = 293

Therefore, it is possible for Fred to raise his average from 178 to 183 in a single game, but he must bowl 293 in his next game to do this.