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LuckyWell [14K]
3 years ago
8

What is the value of x in 145.95-2x=-4.05?

Mathematics
1 answer:
kotykmax [81]3 years ago
3 0
145.95 - 2x = -4.05
subtract -145.95 from both side of the equation
-2x = -4.05 - 145.95
-2x = -150
Divide both sides by -2
-2x/2 = -150/2

x = 75
Final answer

Hope this helps!!!!
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Make d the subject of this formula<br><br> H=d/3+2
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Step-by-step explanation:

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3 years ago
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A group issimpleif it has no nontrivial proper normal subgroups. LetGbe a simple group of order168. How many elements of order 7
stepladder [879]

Answer:

6*8=48 groups with elements of order 7

Step-by-step explanation:

For this case the first step is discompose the number 168 in factors like this:

168 = 8*3*7= 2^3 *3*7

And for this case we can use the Sylow theorems, given by:

Let G a group of order p^{\alpha} m  where p is a prime number, with m\leq 1 and p not divide m then:

1) Syl (G) \neq \emptyset

2) All sylow p subgroups are conjugate in G

3) Any p subgroup of G is contained in a Sylow p subgroup

4) n(G) =1 mod p

Using these theorems we can see that 7 = 1 (mod7)

By the theorem we can't have on one Sylow 7 subgroup so then we need to have 8 of them.

Every each 2 subgroups intersect in a subgroup with a order that divides 7. And analyzing the intersection we can see that we can have 6 of these subgroups.

So then based on the information we can have 6*8=48 groups with elements of order 7 in G of size 168

3 0
3 years ago
(please answer if you know how to do this, it's due today !!) Solve for x, y and z. No links please
satela [25.4K]

Answer:

x = 4

y = 2√5

z = 3√5

Step-by-step explanation:

There are 3 right triangles here, so we can create 3 expressions using Pythagoras' Theorem:

a² + b² = c²

(where a and b are the legs, and c is the hypotenuse)

smallest triangle:  x² + y² = (x + 2)²

medium triangle: (x + 1)² + y² = z²

largest triangle: (x + 2)² + z² = (x + x + 1)²

rewrite the smallest triangle expression to make y² the subject:

x² + y² = (x + 2)²

⇒ x² + y² = x² + 4x + 4

⇒  y² = 4x + 4

rewrite the medium triangle expression to make z² the subject, substituting y² = 4x + 4:

(x + 1)² + y² = z²

⇒ (x + 1)² + 4x + 4 = z²

⇒ x² + 2x + 1 + 4x + 4 = z²

⇒ z² = x² + 6x + 5

rewrite the largest triangle, substituting z² = x² + 6x + 5 and solve for x:

(x + 2)² + z² = (x + x + 1)²

⇒ (x + 2)² + x² + 6x + 5 = (2x + 1)²

⇒ x² + 4x + 4 + x² + 6x + 5 = 4x² + 4x + 1

⇒  2x² - 6x - 8 = 0

⇒  x² - 3x - 4 = 0

⇒ (x + 1)(x - 4) = 0

⇒ x = -1, x = 4

as x > 0, x = 4 only

Substitute found value for x into y² = 4x + 4 and solve for y:

y² = (4 x 4) + 4

⇒ y² = 20

⇒ y = √20 = 2√5

Substitute found value for x into z² = x² + 6x + 5 and solve for z:

z² = 4² + (6 x 4) + 5

⇒ z² = 45

⇒ z = √45 = 3√5

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3 years ago
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