BRAINLIEST ANSWER!!!! #9 1/4 (5x+2)-1/5(x+3)=2 what’s the solution set?

1 plus 1<br> Plus 4 plus 4444 plus 1928 plus 63626

fenix001 [56]

Answer:

70004

Step-by-step explanation:

1+1+4+4444+1928+63626 = 70004

6 0

3 years ago

Read 2 more answers

WILL MARK BRAINIEST IF CORRECT!!!! Select the correct answer. This table represents a function. Is this statement true or false?

e-lub [12.9K]

Answer:

true

Step-by-step explanation:

doesn't over lap each other

4 0

3 years ago

find the volume of the shaded solid. Round your answer to 2 decimal places if necessary. Use pi=3.14 when necessary. cylinder wi

padilas [110]

Ok so what we have is a large cylinder with a hollow cylindrical tube running thru the center. The volume of the shaded region should be the volume of the entire large cylinder (C) minus the volume of the small cylindrical tube (c): C - c
The volume of any cylinder is the area of the top circle (pi×r^2) times the height (h) of the cylinder, where r=radius of the circle. So: h×pi×r^2
The heights are the same for C and c, so we can call that h in both, which = 30ft. Now C's radius (R) = 1/2 of diameter, which is 18ft. So R = 9ft
c's radius (r) is 1/2 of its diameter, which is 6ft. So r = 3ft. Now we can set it up:
C - c = (h×pi×R^2) - (h×pi×r^2)
*since the h and pi in both formulae are multiplied by the other variable, we can factor that out:
h×pi(R^2) - h×pi(r^2) = h×pi(R^2-r^2)
h×pi = 30ft.×3.14 = 94.2ft. -->
94.2ft(9ft^2-3ft^2) = 94.2ft(81-9ft^2)
= 94.2ft(72ft^2) = 6782.4 ft.^3

7 0

3 years ago

Round your answer to the nearest hundredth.

nika2105 [10]

Answer:

5.52umit

$sin65 = \frac{ac}{ab} = \frac{5}{ab} \\ ab = \frac{5}{sin65} = 5.52 \\ ab = 5.52umit$

5 0

2 years ago

Find the volume of each pyramid or come. Round to the nearest tenth if necessary.

Naya [18.7K]

QUESTION 1

The given pyramid has a square base.

The volume of this square pyramid is given by;

$V=\frac{1}{3}\times l^2\times h$

where $l=5ft$ is the length of a side of the square base.

and $h=8ft$ is the height of the pyramid.

We substitute the values into the formula to get;

$V=\frac{1}{3}\times 5^2\times 8 ft^3$

$V=66.7 ft^3$

QUESTION 2

The given pyramid has a rectangular base.

The volume of this rectangular pyramid is given by;

$V=\frac{1}{3}\times l\times b\times h$

where $l=7cm$ and w=4cm are the length and width of a side of the rectangular base.

and $h=8cm$ is the height of the pyramid.

We substitute the values into the formula to get;

$V=\frac{1}{3}\times 7\times 4\times 8cm^3$

QUESTION 3

The given pyramid has a rectangular base.

The volume of this rectangular pyramid is given by;

$V=\frac{1}{3}\times l\times b\times h$

where $l=10in.$ and w=8in are the length and width of a side of the rectangular base respectively.

There is a right triangle created inside this pyramid that can help us find the height of this pyramid.

Notice that the base of this right triangle is half the width of the rectangular base (4in.) and the hypotenuse is 14in.

We need to use Pythagoras Theorem to find the height of this pyramid.

$h^2+4^2=14^2$

$h^2+16=196$

$h^2=196-16$

$h^2=180$

$h=\sqrt{180}$

$h=6\sqrt{5}in.$

We substitute the values into the formula to get;

$V=\frac{1}{3}\times 10\times 8\times6\sqrt{5}in^3$

$V=160\sqrt{5}in^3$

$V=357.8in^3$

QUESTION 4

The radius of the base of the given cone is 12m.

The height of the cone is 25m.

The volume of a cone is calculated using the formula;

$V=\frac{1}{3}\pi r^2h$

We substitute the given values to get;

$V=\frac{1}{3}\pi 12^2\times 25m^3$

$V=3769.9m^3$

QUESTION 5

The given cone has diameter 14yd.

The radius is half the diameter, r=7yd

The radius(7yd), the height (h), and the slant height(25yd being the hypotenuse) form a right triangle.

We apply the Pythagoras Theorem again to get;

$h^2+7^2=25^2$

$h^2+49=625$

$h^2=625-49$

$h^2=576$

$h=\sqrt{576}$

$h=24$

The height of the cone is 24yd.

The volume of a cone is calculated using the formula;

$V=\frac{1}{3}\pi r^2h$

We substitute the given values to get;

$V=\frac{1}{3}\pi 7^2\times 24yd^3$

$V=1231.5yd^3$

QUESTION 6

The height of the given cone is 18mm.

The radius can be calculated using the tangent ratio.

$\tan(66\degree)=\frac{18}{r}$

$r=\frac{18}{\tan(66\degree)}$

$r=8.0141yd$

The volume of a cone is calculated using the formula;

$V=\frac{1}{3}\pi r^2h$

We substitute the given values to obtain;

$V=\frac{1}{3}\pi 8.0141^2\times 18mm^3$

$V=151.1mm^3$

7 0

3 years ago