Not really sure of this one but i think it's like this-
2/10 (money for story) + 3/10 (26.80 dollars to brother)= 1/2 of his money
3/10x=26.80 268=3x ; x= 89.33333....
89.33 X 5/10= answer
money left= (roughly) 44.67
Answer:
y = 5x/7 + 10/-7
Step-by-step explanation:
subtract 5x from both side and you should get -7y = -5x + 10
divide negative 7 into both side -7/-7 = -5x/-7 + 10/-7
and the answer is y = 5x/7 + 10/-7
Answer:
It will be worth about £885.59.
Step-by-step explanation:
The art piece originally costs £600.
And it appreciates at a rate of 3.97% each year.
And we want to find the value of the art after 10 years.
We can write an exponential function to model the situation. The standard exponential function is given by:
Where <em>t</em> is the time in years.
Since it appreciates at a rate of 3.97% each year, the value after each year will be (100% + 3.97%) or 103.97%.
103.97% = 1.0397. So, <em>r</em> = 1.0397:
Our <em>a</em> is the initial value. Therefore:
Then the value of the piece of art after 10 years is:
It will be worth about £885.59 after 10 years.
Answer:
The oil slick area A exhibits exponential growth. Assume time t is measured in days.
dAdt=kA,A0=20,A1=20×3=60
Solve this separable differential equation.
dAdt=kA
∫dAA=∫kdt⟺ln(A)=kt+C
A(t)=A0ekt
Determine the constant k using the initial and first day oil slick area values A0,A1.
A1=A0ek×1 on day one
k=ln(A1A0)=ln(6020)=ln(3)
Substitute the known constant k and A0 into the equation.
A(t)=20eln(3)t
Verify the model A(t) matches the desired oil slick expansion. Does it triple every day?
A(0)=20e0=20
A(1)=20eln(3)1=60=3×20
A(2)=20eln(3)2=180=3×60
A(3)=20eln(3)3=540=3×180
It checks out!
On what day has the oil slick reached 1 hectare? The area is measured in square meters.
1 hectare = 10,000 square meters
10000≤20eln(3)t Solve for t days.
t≥1ln(3)ln(1000020)
t≥5.657 days
Answer
The oil slick reached 1 hectare after about 5+1/2 days.
Step-by-step explanation:
