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grandymaker [24]
3 years ago
13

Find the equation of the exponential function represented by the table below:

Mathematics
1 answer:
Hoochie [10]3 years ago
8 0

Answer:

f(x)=5(4)^x

Step-by-step explanation:

The exponential function is f(x)=ab^x.  a is the initial value of the function, or the y-value when x=0. In this case, a=5. If we enter that into the equation:

f(x)=5b^x

Then we can use another point to solve for b.

20=5b^1

Since anything raised to the power of 1 remains the same, we can continue to solve algebraically.

20=5b\\\frac{20}{5}=\frac{5b}{5}\\b=4

Now that we have both the a and b value, we can return to the exponential function and fill in the blanks.

f(x)=5(4)^x

I hope this helps!

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cos 30=y/32

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135x7 in standered form
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there are 278 houes in hannahs neighborhood she collected a total of $780 from her neighbors to donate to a local charity hannah
Mrrafil [7]
Divide the amount of money earned by the amount she got from every house.

780 / 5 = 156

156 out of 278 houses payed money. Subtract to see how many did not pay money

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3 0
3 years ago
find the height of a rectangular prism with a volume of 125 cubic centimeters, a length of 5 centimeters, and a width of 5 centi
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8 0
3 years ago
Insert five arithmetic means between 14 and86​
konstantin123 [22]

Answer:

The five arithmetic means between 14 and 86 are 26,38,50,62,74

Step-by-step explanation:

We need to find five arithmetic means between 14 and 86

The formula used to find arithmetic mean is: a_{n}=a_{1} +(n-1)d

Where n is the number of terms and d is the common difference

We are given 1st and 7th term.

Using 7th term to find value of d

a_{n}=a_{1} +(n-1)d\\a_{7}=14 +(7-1)d\\86=14+6d\\86-14=6d\\72=6d\\d=\frac{72}{6}\\d=12

So, difference between each term d is 12

Now finding five arithmetic terms i.e a₂, a₃, a₄, a₅, a₆

Using the formula a_{n}=a_{1} +(n-1)d to find terms

Finding term a₂

a_{n}=a_{1} +(n-1)d\\a_{2}=14 +(2-1)12\\a_{2}=14 +12\\a_{2}=26

Finding term a₃

a_{n}=a_{1} +(n-1)d\\a_{3}=14 +(3-1)12\\a_{3}=14 +2*12\\a_{3}=38

Finding term a₄

a_{n}=a_{1} +(n-1)d\\a_{4}=14 +(4-1)12\\a_{4}=14 +3*12\\a_{4}=50

Finding term a₅

a_{n}=a_{1} +(n-1)d\\a_{5}=14 +(5-1)12\\a_{5}=14 +4*12\\a_{5}=62

Finding term a₆

a_{n}=a_{1} +(n-1)d\\a_{6}=14 +(6-1)12\\a_{6}=14 +5*12\\a_{6}=74

So, the five arithmetic means between 14 and 86 are 26,38,50,62,74

7 0
3 years ago
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