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GaryK [48]
3 years ago
12

How many x-intercepts does the graph of y = 2x^2 – 8x + 5 have?

Mathematics
2 answers:
nydimaria [60]3 years ago
8 0
A graph of the equation shows the appropriate choice to be
  C. 2

_____
If you would rather, you can look at the value of the discriminant. For the equation y = ax²+bx+c, the discriminant (d) is
  d = b²-4ac
For your equation, this evaluates to
  d = (-8)²-4(2)(5) = 64 -40 = 24
When the discriminant is positive, the function has two real roots (2 x-intercepts). When it is zero, there is only one x-intercept, and when it is negative, there are none (the roots are complex).

MatroZZZ [7]3 years ago
8 0

Answer:

2

Step-by-step explanation:

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What’s is the inverse function of a(m)=0.6735e^0.423m
natta225 [31]

Answer:

a^{-1}(m)=\frac{ln(\frac{m}{0.6735})}{0.423}

Step-by-step explanation:

The function is  a(m)=0.6735e^{0.423m}

Changing functional notation of a(m) to y:

y=0.6735e^{0.423m}

Now, interchanging m and y:

m=0.6735e^{0.423y}\\

Now, solving for y:

e^{0.423y}=\frac{m}{0.6735}\\ln[e^{0.423y}]=ln[\frac{m}{0.6735}]\\0.423y=ln(\frac{m}{0.6735})\\y=\frac{ln(\frac{m}{0.6735})}{0.423}

Thus, the inverse function is:

a^{-1}(m)=\frac{ln(\frac{m}{0.6735})}{0.423}

5 0
3 years ago
Jimmy invests $2500 in an account with a 5% interest rate, making no other deposits or withdrawals. What will Jimmy’s account ba
Alik [6]

Answer:

We conclude that the total amount accrued, principal plus interest,  from compound interest on an original principal of  $2500 at a rate of 5% per year compounded 6 times per year over 8 years is $3723.38.

Step-by-step explanation:

Given

Principle P = $2500

Interest rate r = 5% = 0.05

Time period t = 8 years

To determine

Accrue Amount A = ?

Using the compound interest equation

A\:=\:P\left(1\:+\:\frac{r}{n}\right)^{nt}

where:

A represents the Accrue Amount

P represents the Principal Amount

r represents the interest rate

t represents the time period in years

n represents the number of compounding periods per unit t

Important tip:

  • Given that the interest is compounded 6 times each year, therefore, the value of n = 6.

now substituting P = 2500, r = 0.05, t = 8 and n = 6 in the equation

A\:=\:P\left(1\:+\:\frac{r}{n}\right)^{nt}

A=2500\left(1+\frac{0.05}{6}\right)^{\left(6\right)\left(8\right)}

\:A=2500\left(1+\frac{0.05}{6}\right)^{48}

A=2500\times 1.48935      ∵  \left(1+\frac{0.05}{6}\right)^{48\:\:}=1.48935

A=\:3723.38 $

Therefore, we conclude that the total amount accrued, principal plus interest,  from compound interest on an original principal of  $2500 at a rate of 5% per year compounded 6 times per year over 8 years is $3723.38.

8 0
2 years ago
I think its C, not sure
Alona [7]
Yes; you are correct.
___________________________________________________
The correct answer is:
___________________________________________________
Answer choice:  [C]:  " x³ − 9x² + 23x <span>− 12 " .
___________________________________________________
Note: (a </span>− b) (c − d + e) = ac − ad + ae − bc + bd − be ;
___________________________________________________
          (x − 4) (x² <span>− 5x + 3) = 

   x * x</span>² = x³ <span>− 

   x * 5x = 5x</span>² + 

   x * 3   = 3x <span>−

   4 * x</span>²  = 4x² <span>−

   -4 * 5x =  -20x +

   -4 * 3 =  -12; 
________________________________________
</span>          (x − 4) (x² − 5x + 3) = 

x³ − 5x² + 3x −4x² − (-20x) + (-12) ;

=  x³ − 5x² + 3x −4x² + 20x − 12 ;

= x³ − 5x² − 4x² + 3x + 20x − 12 ;

= x³ − 9x²  + 23x − 12 ;  which is:
__________________________________________________
Answer choice:  [C]:  " x³ − 9x²  + 23x − 12 " .
__________________________________________________
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3 years ago
The mean game scores and standard deviations of four seasons of a football team are given below. Season Mean Standard Deviation
timurjin [86]
To find the margin of error, multiply the z-score by the standard deviation, then divide by the square root of the sample size.The z*-score for a 90% confidence level is 1.645.The margin of error is 0.20.The confidence interval is 48.3 to 48.7.48.8 is not within the confidence interval. 
7 0
3 years ago
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Solve the proportion.<br> u/2 = 4/1 <br><br> U=
Lelechka [254]

\dfrac{u}{2}  =  \dfrac{4}{1}

\implies \: u \:  =  \frac{4}{1}  \times 2

\implies \: u = 8

3 0
3 years ago
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