1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
jeka94
3 years ago
11

Find the measures of m and n.

Mathematics
1 answer:
hodyreva [135]3 years ago
6 0

Answer:

m = 4

n = 5

Step-by-step explanation:

m + 8 = 3m\\\\m - 3m = - 8\\\\-2m = - 8\\\\m = 4

2n - 1 = 9 \\\\2n = 9 + 1\\\\2n = 10\\\\n = 5

You might be interested in
How can you use a right angle to dicide how to name another angle?
DanielleElmas [232]
If it is a square, subtract (90+ whatever the other angle is) from 360. If it is a triangle than add 90 plus whatever other number the other angle is then subtract it from 180. A triangle is 180 degrees, and a square is 360 degrees.
5 0
2 years ago
Which of the following functions have a vertical asymptote for values of Ø such that cos Ø = 1?Select all that apply.
igomit [66]

Answer:

y=\cot \theta and y=\csc \theta

Step-by-step explanation:

Note that if \cos \theta=1, then \sin \theta=0.

Functions y=\cos \theta,\ \ y=\sin \theta do not have vertical asymptotes at all.

Vertical asymptotes have functions y=\tan \theta,\ \ y=\cot \theta,\ \ y=\sec \theta,\ \ y=\csc \theta.

Functions y=\tan \theta and y=\sec \theta have the same vertical asymptotes (when \cos \theta =0).

Functions y=\cot \theta and y=\csc \theta have the same vertical asymptotes (when \sin \theta =0). See attached diagram

3 0
3 years ago
The hypotenuse of a right triangle has endpoints A(4, 1) and B(–1, –2). On a coordinate plane, line A B has points (4, 1) and (n
GarryVolchara [31]

Answer:

(-1,1),(4,-2)

Step-by-step explanation:

Given: The hypotenuse of a right triangle has endpoints A(4, 1) and B(–1, –2).

To find: coordinates of vertex of the right angle

Solution:

Let C be point (x,y)

Distance between points (x_1,y_1),(x_2,y_2) is given by \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

AC=\sqrt{(x-4)^2+(y-1)^2}\\BC=\sqrt{(x+1)^2+(y+2)^2}\\AB=\sqrt{(4+1)^2+(1+2)^2}=\sqrt{25+9}=\sqrt{34}

ΔABC is a right angled triangle, suing Pythagoras theorem (square of hypotenuse is equal to sum of squares of base and perpendicular)

34=\left [ (x-4)^2+(y-1)^2 \right ]+\left [ (x+1)^2+(y+2)^2 \right ]

Put (x,y)=(-1,1)

34=\left [ (-1-4)^2+(1-1)^2 \right ]+\left [ (-1+1)^2+(1+2)^2 \right ]\\34=25+9\\34=34

which is true. So, (-1,1) can be a vertex

Put (x,y)=(4,-2)

34=\left [ (4-4)^2+(-2-1)^2 \right ]+\left [ (4+1)^2+(-2+2)^2 \right ]\\34=9+25\\34=34

which is true. So, (4,-2) can be a vertex

Put (x,y)=(1,1)

34=\left [ (1-4)^2+(1-1)^2 \right ]+\left [ (1+1)^2+(1+2)^2 \right ]\\34=9+4+9\\34=22

which is not true. So, (1,1) cannot be a vertex

Put (x,y)=(2,-2)

34=\left [ (2-4)^2+(-2-1)^2 \right ]+\left [ (2+1)^2+(-2+2)^2 \right ]\\34=4+9+9\\34=22

which is not true. So, (2,-2) cannot be a vertex

Put (x,y)=(4,-1)

34=\left [ (4-4)^2+(-1-1)^2 \right ]+\left [ (4+1)^2+(-1+2)^2 \right ]\\34=4+25+1\\34=30

which is not true. So, (4,-1) cannot be a vertex

Put (x,y)=(-1,4)

34=\left [ (-1-4)^2+(4-1)^2 \right ]+\left [ (-1+1)^2+(4+2)^2 \right ]\\34=25+9+36\\34=70

which is not true. So, (-1,4) cannot be a vertex

So, possible points for the vertex are (-1,1),(4,-2)

7 0
3 years ago
Read 2 more answers
Fosmine lounches a model rocket from a elift. The rocket goes up 16.8 feet above the cliff,
7nadin3 [17]

Answer: The final answer I got is -44.9

Step-by-step explanation:  At the first chose I put Positive, then at the second choise I put negative, at the third choose I put 16.8-(-28.1), and at the last choice I put -44.9.

3 0
3 years ago
5. A study found that the average time it took a person to find their dream home was 5.9 months. If a sample of
solong [7]

Answer:

The 95% confidence interval of the mean time it took a person to find their dream home is between 5.64 months and 6.16 months.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.025 = 0.975, so z = 1.96

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.96\frac{0.8}{\sqrt{36}} = 0.26

The lower end of the interval is the sample mean subtracted by M. So it is 5.9 - 0.26 = 5.64 months

The upper end of the interval is the sample mean added to M. So it is 5.9 + 0.26 = 6.16 months.

The 95% confidence interval of the mean time it took a person to find their dream home is between 5.64 months and 6.16 months.

4 0
3 years ago
Other questions:
  • Which situation is best represented by the following equation?<br> 45w + 123.95<br> 753.95
    5·1 answer
  • Sara bought a 20 ounces jar of strawberry jam for $4 what is the unit price
    15·1 answer
  • How to solve for h? I don't understand it
    10·1 answer
  • What is the relationship among direct variation,lines,rates of change,and slope
    12·1 answer
  • Sele
    12·1 answer
  • Please do this i will give brainlieast and will give 75 points. go to this and and enter the right stuff!
    11·1 answer
  • Find the area of the following rectangle,
    9·1 answer
  • Help fastttttttttttt quickkkk
    6·2 answers
  • Y’all I need help fast
    10·1 answer
  • Lily paid $208.50 for 2 identical necklaces and 3 purses. Serena paid $91.50 for 1 such necklace and 1 purse. Each purse cost th
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!