To find the perimeter of this blue figure, add together the shown lengths of the six sides.
The three measurements on the top have the LCD 4, so we combine 14 3/4, 4 2/4 and 8 2/4. The sum is 26 7/4, or 27 3/4, or 27.75.
The three measurements on the bottom share the LCD 5, so we can immediately combine them, obtaining 32 8/5, or 33 3/5, or 33.60.
Combining 27.75 and 33.60 results in 61.35, or 61 35/100, or 61 7/20.
The perimeter of the given figure is 61 7/20.
Answer to 1: 648
Answer to 2: 175
perimeter =QR+RS+ST+TU+UQ =26.1
RQ = 5.39
RS = 4.47
ST = 3.61
TU = 4.12
UQ = 8.54
Answer:
225 frogs
Step-by-step explanation:
Total population of frogs = 300 frogs.
Observed population of frogs = 24
6 of the 24 observed frogs had spots
Which means , the number of frogs that did not have spots = 24 - 6 = 18 frogs.
We were told to find how many of the total population can be predicted to NOT have spots. We would form a proportion.
If 24 frogs = 18 frogs with no spots
300 frogs = Y
Cross multiply
24Y = 300 × 18
Y = (300 × 18) ÷ 24
Y = 5400 ÷ 24
Y = 225 frogs.
This means out of 300 frogs, 225 frogs do not have spots.
Therefore, the total population that can be predicted to NOT have spots is 225 frogs.
the total population can be predicted to NOT have spots
Answer:
I dont know you never explain properly
Step-by-step explanation:
