Answer:
OH²=412
Step-by-step explanation:
A Circumcenter of a triangle is the point where the three perpendicular bisectors of a triangle meet.
The Orthocenter is the point where all three altitudes of the triangle intersect.
Given any triangle, the orthocenter, circumcenter and centroid are collinear on the Euler line. By Euler's Identity, the distance between the circumcenter and the orthocenter of a triangle is related to the circumradius(R) and the sides(a,b,c) of the triangle by the relation
OH²=9R²-(a²+b²+c²)
R=7, a²+b²+c²=29
OH²=9(7)²-29
OH²=412
Step-by-step explanation:
Surface area of a cylinder:
A = (2 x pi x r x h) + (2 x pi x r^2)
(2 x pi x 5 x 25) + (2 x pi x 5^2)
785.3981 + 157.0796 = 942.4777cm^2
Volume of cylinder:
V = pi x r^2 x h
pi x 5^2 x 25 = 1963.4954cm^3
You are given Maggie's planning on going to Penn State University. You are also given that she could live there if she has more than $2,000 if she already bought a laptop at $450.
For part A, the inequality that we can form is x ≥ 2,450 because she needs more than $2,000 to survive after buying a $450 dollar worth laptop. Adding the two makes it 2,450.
For part B, if she has to withdraw $30 per week, then the inequality that we can form is x ≥ 2,450 - 30
For part C,
30x ≥ 2,000
x ≥ 66.67
For part D, the answer 66.67 means that Maggie can have 66 times to withdraw $30 per week worth of food from her balance $2000.
Answer:
B, 2(10^4)
Step-by-step explanation:
2(10^3)= 2000
2(10^4)= 20000
2(10^4) Is closer to 16790 than 2(10^3)
Answer:
First picture - 20.42 m
Second picture - 12.9 m
Step-by-step explanation:
------------------------------------------------------------------------------------------------------------
Formula for pyramid:
Where,
b = base - 3.5 m
h = height - 5 m
Thus,
≈ 
------------------------------------------------------------------------------------------------------------
Formula for pyramid:
Where,
b = base - 3 m
h = height - 4.3 m
Thus,
------------------------------------------------------------------------------------------------------------
<u><em>Kavinsky</em></u>
