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Orlov [11]
2 years ago
6

I’m lazy:) I’ll give brainliest

Mathematics
2 answers:
iren2701 [21]2 years ago
8 0

Answer:

5.790

Step-by-step explanation:

all zeos at the top

FinnZ [79.3K]2 years ago
4 0

Answer:

its 5.795

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
A curve is given by y=(x-a)√(x-b) for x≥b, where a and b are constants, cuts the x axis at A where x=b+1. Show that the gradient
ankoles [38]

<u>Answer:</u>

A curve is given by y=(x-a)√(x-b) for x≥b. The gradient of the curve at A is 1.

<u>Solution:</u>

We need to show that the gradient of the curve at A is 1

Here given that ,

y=(x-a) \sqrt{(x-b)}  --- equation 1

Also, according to question at point A (b+1,0)

So curve at point A will, put the value of x and y

0=(b+1-a) \sqrt{(b+1-b)}

0=b+1-c --- equation 2

According to multiple rule of Differentiation,

y^{\prime}=u^{\prime} y+y^{\prime} u

so, we get

{u}^{\prime}=1

v^{\prime}=\frac{1}{2} \sqrt{(x-b)}

y^{\prime}=1 \times \sqrt{(x-b)}+(x-a) \times \frac{1}{2} \sqrt{(x-b)}

By putting value of point A and putting value of eq 2 we get

y^{\prime}=\sqrt{(b+1-b)}+(b+1-a) \times \frac{1}{2} \sqrt{(b+1-b)}

y^{\prime}=\frac{d y}{d x}=1

Hence proved that the gradient of the curve at A is 1.

7 0
2 years ago
Library 3.5x250 <br><img src="https://tex.z-dn.net/?f=3.5%20%5Ctimes%20500%20%3D%20" id="TexFormula1" title="3.5 \times 500 = "
Elodia [21]
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7 0
3 years ago
Which of the following inequalities has no solutions?
neonofarm [45]

Answer:

  • A) x > 3 and x < 2 has no solutions

Step-by-step explanation:

Given inequalities below and we are looking for a pair with no solution.

Let's verify:

A) x > 3 and x < 2,

  • It has no solutions since the two inequalities have no common interval.

B) x > - 3 and x < - 2,

  • Its solution is -3 < x < - 2, the interval between two given endpoints.

C) x > - 3 and x < 2,

  • Similar to option B, the interval is between two endpoints:
  • - 3 < x < 2

D) x > - 3 and x > - 2,

  • Its solution is x > - 2, the two inequalities cover almost same interval.
8 0
1 year ago
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