Hypothenuse is the longest side
You can see the X is the longest
Solution: A. X
1.) 4(x+3)
Find the GCF, Greatest Common Factor, of 4x and 12.
4x=2*2*x
12=3*2*2
The greatest common factor is 4. Put this outside of the parentheses. (You would multiply the 2*2)
Then, put the rest of the factors as a sum. (Only the factors on the same line.)
Solution: 4(x+3)
To check, distribute to see if it works.
4x+12
2.) 2(4r+7)
Find the GCF of 8r and 14
8r=2*2*2*r
14= -1*7*2
The greatest common factor is 2. (There is only 1 two, so you would not multiply them.)
Then, put the rest of the factors as a sum. (Only the factors on the same line.)
Multiply the 2*2*r as one addend and the -1*7 as the other.
Solution: 2(4r-7)
To check, distribute to see if it works.
8r-14
Do you get it now?
3.) 5(x+7)
4.) 7(2x+1)
5.) Cannot be factored.
32x-15
Find the GCF of 32x and -15
32x: 2*2*2*2*2*x
-15: -1*5*3
Because there are no similar factors other than 1, it cannot be factored.
6.) 8(4x+3)
7.) 3(2x-3)
8.) 24(1x+2)
9.) 9(-2x+8)
10.) Cannot be factored
11.) 8(1x+3)
12.) 50(1x+5)
The intersection of the steps is just a fancy way of asking wi\hich numbers are in both equations so lets look and see :)
The 1st = 0...1...5...7...8
The 2nd =0........5...7........9
Answer = D {0, 5, 7}
Hope this helps have any questions let me know :)
<em>⇨ Use the formula below</em>
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<em>⇨ Substitute the parameters:</em>
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Hope that helped
Hello,
Please write correctly.
g(x)= (2x+3)/(x+1) to be written like a/(x+p) + q
It is very simple!
(2x+3)/(x+1)= [(2x+2)+1]/(x+1)= (2(x+1)+1)/(x+1)= 2+1/(x+1)
