Answer: 4
you have to find prime factors of each number
Answer: 12 red balls must be added
Step-by-step explanation:
Starting out with 15 balls, 6 red implies 9 blue. If blue remains 9, then we expect red to be 18 for a probability at 2/3. 18-6 = 12
<span><span><span><span><span>I am so sorry if this is wrong, but
2−5</span>+4</span>+21</span>+1666666</span>−<span>(2)(43)
</span></span><span>=<span><span><span><span>−3+4</span>+21</span>+1666666</span>−<span>(2)(43)
</span></span></span><span>=<span><span>1+21+1666666</span>−<span>(2)(43)
</span></span></span><span>=<span>22+1666666−<span>(2)(43)
</span></span></span><span>=<span>1666688−<span>(2)(43)
</span></span></span><span>=1666688−86
</span><span>Your answer would be 1,666,602
Hope this helps!:)</span>
Answer:
True.
Step-by-step explanation:
It explains itself right
Answer:
1c

1d

Step-by-step explanation:
From the question we are told that
The probability of telesales representative making a sale on a customer call is 
The mean is 
Generally the distribution of sales call made by a telesales representative follows a binomial distribution
i.e
and the probability distribution function for binomial distribution is
Here C stands for combination hence we are going to be making use of the combination function in our calculators
Generally the mean is mathematically represented as

=> 
=> 
Generally the least number of calls that need to be made by a representative for the probability of at least 1 sale to exceed 0.95 is mathematically represented as

=> 
=> ![P( X \ge 1) = 1 - [ ^{n}C_0 * (0.15 )^0 * (1- 0.15)^{n-0}] > 0.95](https://tex.z-dn.net/?f=P%28%20X%20%5Cge%201%29%20%3D%201%20-%20%5B%20%5E%7Bn%7DC_0%20%2A%20%20%280.15%20%29%5E0%20%2A%20%20%281-%200.15%29%5E%7Bn-0%7D%5D%20%3E%200.95)
=> ![1 - [1 * 1* (0.85)^{n}] > 0.95](https://tex.z-dn.net/?f=%201%20-%20%5B1%20%20%2A%20%201%2A%20%20%280.85%29%5E%7Bn%7D%5D%20%3E%200.95)
=> ![[(0.85)^{n}] > 0.05](https://tex.z-dn.net/?f=%20%20%5B%280.85%29%5E%7Bn%7D%5D%20%3E%200.05)
taking natural log of both sides

=> 