Answer:
1/16
Explanation:
Sickle-cell disease is caused by a homozygous recessive genotype <em>dd</em>.
A man and a woman both heterozygous Dd will have the following offspring:
The probability of having a <em>dd</em> child with Sickle-cell disease is 1/4. Each time they have children the gamete combination is random, so the genotype of the second child is independent from the genotype of the first child.
According to rules of probability, if two events are independent from each other, the probability of both happening is calculated by multiplying the individual probabilities of each.
Therefore the probability of having the first two children with the disease is 1/4 x 1/4 = 1/16.
D. Potassium
The formula for phosphoric acid is H3PO4.
Potassium is K, not P.
The genotype of the mother must be heterozygous.
<h3>Punnet' square</h3>
In order to obtain a probability of 25% red-eyed males from the offspring, the mother must be heterozygous for the trait. The father can be of any genotype.
Thus, the likely genotype combination that will result in 25% red-eyed males are:
x 
and 
When you cross the first one above, the genotype of the offspring would be
.
The second cross will give offspring with the genotypes 
Both crosses give a 25% chance of producing re-eye males.
More on Punnet's square can be found here: brainly.com/question/3154616
#SPJ1
They differ from the number and types of organelles they contain