Question

what is an equation of the line that passes through the point (-6,-1) and is perpendicular to the line 6x-y=7? (has to be in y=mx+b form)

Answer 1

Answer:

y = $-\frac{1}{6}$ x - 2

Step-by-step explanation:

Slopes of perpendicular lines are opposite reciprocals.

If AB ⊥ CD , then $m_{AB}$ $m_{CD}$ = - 1

y - $y_{1}$ = m(x - $x_{1}$)

~~~~~~~~~~~

6x - y = 7 ⇔ y = 6x - 7

Slope of given line is 6

Slope of a perpendicular line is $-\frac{1}{6}$

( - 6, - 1 )

y + 1 = $-\frac{1}{6}$ (x + 6)

y = $-\frac{1}{6}$ x - 2