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3 years ago

Write two numbers that are greater than 32.46 and less than 32.56. Then find the difference of your two numbers.

1 answer:

3 0

Answer: Two numbers that are greater than 32.46 and less than 32.56 are 32.48 and 32.52. (Answers may vary, these are just two examples.) The difference between the two are 0.04. (once again, answers may vary.)

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The value of k such that (x-5) divides the polynomial p(x)= x^3-6x^2+kx+30 exactly,is

mixas84 [53]

Answer:

k = - 1

Step-by-step explanation:

If (x - 5) is a factor of p(x) then p(5) = 0

p(5) = 5³ - 6(5)² + 5k + 30 = 0 , that is

125 - 150 + 5k + 30 = 0

5 + 5k = 0 ( subtract 5 from both sides )

5k = - 5 ( divide both sides by 5 )

k = - 1

3 0

3 years ago

Use the figure to find the measures of the numbered angles.

quester [9]

Answer:

$< 1 = 81 \\ < 2 =99 \\ < 3 =81 \\ < 4 = 99\\ < 5 = 81 \\ < 6 =99 \\ < 7 = 81$

8 0

3 years ago

Complete the square for the expression, then factor the trinomial.

astraxan [27]

Answer:

$x {}^{2} - 4x \\ = x(x - 4)$

3 0

3 years ago

Find f. (Use C for the constant of the first antiderivative and D for the constant of the second antiderivative. f"(x) = 2x + 9e

ad-work [718]

Answer:

$f(x)=\frac{x^3}{3}+9e^x+Cx+D$

Step-by-step explanation:

The function F(x) is an antiderivative of the function f(x) on an interval I if

F′(x) = f(x) for all x in I.

The function F(x) + C is the General Antiderivative of the function f(x) on an interval I if F′(x) = f(x) for all x in I and C is an arbitrary constant.

The Indefinite Integral of f(x) is the General Antiderivative of f(x).

$\int {f(x)} \, dx =F(x)+C$

To find the first antiderivative you must integrate the function $f''(x) = 2x + 9e^x$

$f'(x)=\int { 2x + 9e^x} \, dx \\\\\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx\\\\\int \:2xdx+\int \:9e^xdx = x^2+9e^x\\\\\mathrm{Add\:a\:constant\:to\:the\:solution}\\\\x^2+9e^x+C$

To find the second antiderivative you must integrate the function $f'(x) =x^2+9e^x+C$

$f(x)=\int {x^2+9e^x+C} \, dx\\\\\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx\\\\\int \:x^2dx+\int \:9e^xdx+\int \:Cdx= \frac{x^3}{3}+9e^x+Cx\\\\\mathrm{Add\:a\:constant\:to\:the\:solution}\\\\\frac{x^3}{3}+9e^x+Cx+D$

Therefore,

$f(x)=\frac{x^3}{3}+9e^x+Cx+D$

8 0

3 years ago

Calculate 6.75% tax on $2,305. a. $15.56 b. $145.22 c. $146.14 d. $155.59

Dennis_Churaev [7]

D. $155.59 is the correct answer

$2,305*.0675=$155.5875 round to $155.59

6 0

4 years ago

Read 2 more answers