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Mice21 [21]
3 years ago
6

an area of a rectangle city park is 1556 square miles the width of the park is 3/7 miles what is the length in miles of the park

​
Mathematics
1 answer:
alina1380 [7]3 years ago
7 0

Answer:

457

Step-by-step explanation:

value of 1556

explanion

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A plane is flying 3900 m above the ground level. The angle of elevation from the control tower to the plane is
Tcecarenko [31]

The horizontal distance to the control tower is approximately 18506.83m

Data;

  • distance from the ground = 3900m
  • angle of elevation = 11.4 degrees
  • horizontal distance = ?

<h3>Trigonometric Ratio</h3>

To solve this problem, we need to use trigonometric ratio SOHCAHTOA.

In this case, we have the value of opposite and angle and we need to find the adjacent to the angle. The tangent of the angle would be perfect for this.

tan\theta = \frac{opposite}{adjacent} \\tan11.4 = \frac{3900}{x}\\x = \frac{3900}{tan11.4}\\ x = 18506.83m

The horizontal distance to the control tower is approximately 18506.83m

Learn more on trigonometric ratio here;

brainly.com/question/4326804

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2 years ago
X+2 = 7/8 mulltiplied by -15x
Marysya12 [62]

Answer:

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Step-by-step explanation:

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3 0
3 years ago
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KiRa [710]

Answer:

Step-by-step explanation:whtyui

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6 0
3 years ago
Find the distance between xequals[Start 2 By 1 Matrix 1st Row 1st Column 8 2nd Row 1st Column negative 5 EndMatrix ]and yequals[
kherson [118]

Answer:

Distance =√(x₁ - y₁)²+ (x₂ - y₂)² = √97 = 9.85

Step-by-step explanation:

The Matrix X and Y could also be referred to as vectors in Rⁿ dimensions.

if Vector X = ( x₁ , x₂)   and  Vector  Y = (y₁ , y₂)

then, Distance (X-Y) = ||X-Y|| = √(x₁ - y₁)²+ (x₂ - y₂)²

where, x₁ = 8, x₂ = -5   and  y₁ = -1 , y₂ = -9

Distance = √(8 - (-1))²+ (-5 - (-9))² = √9² + 4² =√97 = 9.85

4 0
3 years ago
What is the answer for this
e-lub [12.9K]

Answer:

A

Step-by-step explanation:

The green is the starting place, when you move from a point on the green triangle to the blue one, you go 5 to the left and 3 down.

8 0
3 years ago
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