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stiv31 [10]
4 years ago
15

Helpp Which statement about the inequality `2(1)/(5) < 2(3)/(5)` is true?

Mathematics
1 answer:
lara31 [8.8K]4 years ago
3 0

We are given inequality 2(1)/(5) < 2(3)/(5).

This can be read as : 2(1)/(5) is less than 2(3)/(5).

Therefore, 2(3)/(5) is vertically up than 2(1)/(5).

That is On the vertical number line 2(3)/(5) is up and 2(1)/(5) is located below.

Therefore, correct option is B option.

<h3>B. On the vertical number line, `2(3)/(5)` is located below `2(1)/(5)`.</h3>

All other statements are incorrect.

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Another bowler, Ryan Shafer, has a mean absolute deviation of 5. Based on the mean absolute deviation of Norm Duke, who has been
Wewaii [24]

Answer:

Ryan is a more consistent performer

Step-by-step explanation:

The complete question is

HEL 1. Shown are the final scores for Norm Duke in the past eight bowling tournaments.

299, 281, 285, 269, 280, 269, 286, 287

Part A: What is the mean absolute deviation of Norm Duke’s scores?

A.

7.50

B.

7.00

C.

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D.

6.75

Part B: Based on the mean absolute deviation from Part A, who has been the more consistent bowler if Ryan Shafer has a mean absolute deviation of 7?

Solution

First we will find the mean deviation of Duke is 7.5

The standard deviation of Ryan is 7.0. This means that the average variation in case of Duke is higher than that of average variation of Ryan.

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4 0
3 years ago
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Nimfa-mama [501]

Answer:

Step-by-step explanation:

3 0
3 years ago
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liq [111]

ok so what's the question.

8 0
3 years ago
Albert wants to show that tan(theta)sin(theta)+cos(theta)=sec(theta). He writes the following proof:
Nataly_w [17]
We have that
<span>tan(theta)sin(theta)+cos(theta)=sec(theta)
</span><span>[sin(theta)/cos(theta)] sin(theta)+cos(theta)=sec(theta)
</span>[sin²<span>(theta)/cos(theta)]+cos(theta)=sec(theta)

</span><span>the next step in this proof
is </span>write cos(theta)=cos²<span>(theta)/cos(theta) to find a common denominator
so

</span>[sin²(theta)/cos(theta)]+[cos²(theta)/cos(theta)]=sec(theta)<span>

</span>{[sin²(theta)+cos²(theta)]/cos(theta)}=sec(theta)<span>

remember that 
</span>sin²(theta)+cos²(theta)=1
{[sin²(theta)+cos²(theta)]/cos(theta)}------------> 1/cos(theta)
and 
1/cos(theta)=sec(theta)-------------> is ok

the answer is the option <span>B.)
He should write cos(theta)=cos^2(theta)/cos(theta) to find a common denominator.</span>
6 0
3 years ago
Read 2 more answers
What is the Inverse operation needed to solve for p?<br> 765 = p - 254
KATRIN_1 [288]

Answer:

addition of 254 to both side

4 0
3 years ago
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