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3 years ago

Is 3(5x - 4) = 15x - 12 a one solution , no solution or infinite solutions

Mathematics

1 answer:

vaieri [72.5K]3 years ago

6 0

Answer:

Infinite Solutions

Step-by-step explanation:

3(5x - 4) needs to be simplified

So we multiply 5x by 3

So 3 x 5x = 15x

Then we multiply -4 by 3

3 x -4 = - 12

Put those together we get 15x - 12

The same equation as the one on the right side

So since 15x - 12 = 15x - 12, the x variable can be any number

Also a little tip:

With Forms quizzes, you can hit control + U and find the answers in the code

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Can someone help me on this question.

Temka [501]

46! Because 5 times 3 is 15 and the two big rectangles are equal, that’s 15+15. (30) 5x1 is 5 and THERES two equal things like that so 5+5 (10). 3x1 is 3 and THERES also two equal things so add 3+3. (6) add 30+10+6 which makes 46! :)

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3 years ago

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For which positive integer values of $k$ does $kx^2+20x+k=0$ have rational solutions? Express your answers separated by commas a

Musya8 [376]

Answer:

-10,10

Step-by-step explanation:

The given quadratic equation is

$k {x}^{2} + 20x + k = 0$

The discriminant of this equation is given by;

$D = {b}^{2} - 4ac$

where a=k, b=20, c=k

For rational solutions, the discriminant must be zero.

${20}^{2} - 4 \times k \times k = 0$

Simplify to get:

$400 - 4 {k}^{2} = 0$

This implies that:

$400 = 4 {k}^{2}$

$100 = {k}^{2}$

Take square root to get:

$k = \pm\sqrt{100}$

$k = \pm10$

$k = - 10 \: or \: k = 10$

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3 years ago

4x + y = 3<br>-x + 2y = -3<br>I need to use substitution to solve this. help?

IrinaK [193]

Answer:

(x,y) (1,-1)

Step-by-step explanation:

y=3-4x

-x+2y=-3

x+2(3-4x)=-3

x=1

y=3-4*1

y=-1

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Help please thank you

Artemon [7]

The answer is Yes, no, yes, no

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3 years ago

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