We have points (-3, 4), (-1, 2), (4, -3) and (6,-5)
Let's verify it's a line by calculating the slopes between successive points.
Slope is change in y over change in x.
(2 - 4)/(-1 - -3) = -2/2 = -1
(-3 - 2)/(4 - -1) = -5/5 = -1
(-5 - -3)/(6 - 4) = -2/2 =-1
Yup. We have a line of slope -1 through point (-1, 2)
y - 2 = -1(x - -1)
y = -x - 1 + 2
y = -x + 1
That's the linear equation for the table.
Answer: Linear equation: y = -x + 1 slope = -1
Answer:
Step-by-step explanation:
Given expression:
![\left[(-4)^5\right]^3](https://tex.z-dn.net/?f=%5Cleft%5B%28-4%29%5E5%5Cright%5D%5E3)
Try them and see.
For the first:
3(-3) + 0 = -9 . . . . not > -8
3(-2) + (-1) = -7 . . . is > -8 . . . . . 2) (-2, -1) is a solution
For the second:
4 - 4(-2) = 12 . . . . not ≤ -6
-2 -4(1) = -6 . . . . . is ≤ -6 . . . . . . 2. (1, -2) is a solution
Answer:
x = 3, y = 2.
Step-by-step explanation:
I assume that O is the point of intersection of the diagonals. The diagonals of a parallelogram bisect each other so here we have AO = OC and DO = OB.
Therefore 5y + 1 = 6y - 1
1 + 1 = 5y - 5y
2 = y.
2(x + 1) = 3x - 1
2x + 2 = 3x - 1
2 + 1 = 3x - 2x
3 = x.
