<h3>
Answer:</h3>
a. -(3√13)/13
<h3>
Step-by-step explanation:</h3>
The cosine can be found from the tangent by way of the secant.
tan(θ)² +1 = sec(θ)² = 1/cos(θ)²
Then ...
cos(θ) = ±1/√(tan(θ)² +1)
The <em>cosine is negative in the second quadrant</em>, so we will choose that sign.
cos(θ) = -1/√((-2/3)² +1) = -1/√(4/9 +1) = -1/√(13/9)
cos(θ) = -3/√13 = -(3√13)/13 . . . . . matches your selection A
I hope it helps you get it right
Only Statement 2 is surely correct.
because there maybe chances that the line L1 and L3 lies above the line L2 and they can also fulfill the condition of perpendicularity so we can't be sure about statement 3 & statement 1 is clearly incorrect
Answer:
r = 5sec(θ)
Step-by-step explanation:
The usual conversion is ...
y = r·sin(θ)
x = r·cos(θ)
__
The second of these can be used here.
r·cos(θ) -5 = 0
r·cos(θ) = 5
r = 5/cos(θ) = 5sec(θ)
A suitable polar equation is ...
r = 5sec(θ)
