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love history [14]
3 years ago
5

Which orded pair is a solution of the equation 2x+4y=6x-y

Mathematics
1 answer:
Evgen [1.6K]3 years ago
7 0
Y=4/5x hope that’s the right answer
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Plz help well mark brainliest if you are correct!!…
erik [133]

Answer:

A. y<-3

Step-by-step explanation:

6 0
2 years ago
Organize the following expressions from greatest to least by number of terms:
vitfil [10]
To organize the expressions according to the number of terms, you should understand what a term is. A term is either a single number or variable, or numbers and variables multiplied together. Terms are separated by + or − signs. It is organized as follows:

2x2y + x2 - 3x + 4
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3 years ago
Given f(x) = 3x + 1, solve for x when f(x) = 7.
irakobra [83]

Answer:

f(7) = 22 or x =2

Step-by-step explanation:

  1. f(x) = 3x + 1
  2. f(7) = 3(7) + 1
  3. f(7) = 21 + 1
  4. f(7) = 22

<u>Or if the equation meant it like this:</u>

  1. f(x) = 3x + 1
  2. 7 = 3x + 1
  3. 6 = 3x
  4. 2 = x
4 0
3 years ago
Read 2 more answers
PLEASE HELP!! WILL MARK BRAINLIEST AND HELP YOU!!!
bearhunter [10]

given: s is the midpoint of rt

definition of midpoint: rs st

given: st xg

transitive property of congruence: rs xy

5 0
3 years ago
List the ordered pairs in the equivalence relations produced by these partitions of {a, b, c, d, e, f, g}: a) {a,b},{c,d},{e,f,g
finlep [7]

Answer:

a)  {a,b} , {c,d} , {e,f,g},{a , b } = {(a,a) (b,b) (a,b) (b,a)},{c , d } = {(c,c) (d,d) (c,d) (d , c) } ,{e,f,g} = {(e,e) (e,f)  (f,e) (e,g) (f,f) (f,g) ( g,e) (g,f)(g,g)}  

b) { (a,a)(b,b)(c,c)(c,d)(d,c)(d,d)(e,e)(e,f)(f,e)(f,f)(g,g)

c)  {(a,a)(a,b)(b,b)(b,a)(a,c)(c,a)(b,c)(c,b)(c,c)(d,a)(a,d)(b,d)(d,b)(d,c)(c,d)(d,d)(c,c)(c,f)(f,c)(f,f)(c,g)(g,c)(f,g)(g,f)(g,g)

Step-by-step explanation:

a) {a,b} , {c,d} , {e,f,g}

  {a , b } = {(a,a) (b,b) (a,b) (b,a)}

  {c , d } = {(c,c) (d,d) (c,d) (d , c) }

  {e,f,g} = {(e,e) (e,f)  (f,e)  (e,g) (f,f) (f,g) ( g,e) (g,f) (g,g)}  

b) {a} ,{b},{c,d} ,{e,f},{g}

     { (a,a)(b,b)(c,c)(c,d)(d,c)(d,d)(e,e)(e,f)(f,e)(f,f)(g,g)}

c)  {a,b,c,d},{e,f,g}

   {(a,a)(a,b)(b,b)(b,a)(a,c)(c,a)(b,c)(c,b)(c,c)(d,a)(a,d)(b,d)(d,b)(d,c)(c,d)(d,d)(c,c)(c,f)(f,c)(f,f)(c,g)(g,c)(f,g)(g,f)(g,g)

4 0
3 years ago
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