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g100num [7]
3 years ago
13

Solve the math problem

Mathematics
2 answers:
Karo-lina-s [1.5K]3 years ago
5 0

Answer:

\frac{ - 4y^{6} {k}^{2}  }{ - 8 {y}^{9} {k}^{5}  }

=  \frac{1}{2 {y}^{3} {k}^{3}  }

DiKsa [7]3 years ago
4 0

Answer:

1 / 2y³k³

Step-by-step explanation:

Simplifying

=> -4y⁶k² / -8y⁹k⁵

=>  1 / 2y³k³

=> or (2y³k³)⁻¹

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What's 2 over 5th plus 2 over 10th
sergij07 [2.7K]

The expression we need to solve is:

\frac{2}{5}+\frac{2}{10}

To solve this problem, we need to not that we can simplify the fraction 2/10 by dividing both number by 2:

6 0
2 years ago
Solve for u.<br> 4+3u = -2<br> Simplify your answer as much as possible.
Elza [17]

Answer:

-2

Step-by-step explanation:

4+3u=-2

3u=-2-4

u=-6/3

u=-2

8 0
4 years ago
Read 2 more answers
Anyone here able to lend a helping hand?
elena55 [62]

Answer:

Step-by-step explanation:

1). Vertical intercept of the graph = Point at which the graph intersects the y-axis.

Therefore, vertical intercept is y = 1000.

In this situation vertical intercept means the initial dose of the drug taken = 1000 mg.

2). From the graph attached, point (x, y) represents,

x = Time 't' or duration

y = concentration of the drug after time 't'

Point (0, 1000) represents concentration = 1000 mg of the drug after t = 0 hour

Similarly, (1, 750) represents concentration = 750 mg after t = 1 hour

Therefore, fraction of drug remained = \frac{750}{1000}

                                                              = \frac{3}{4}

3). Let the equation, representing the concentration of the drug and time is,

y=a(b)^t

Here, a = Initial amount of the drug (at t = 0 hours)

            = 1000 mg

At (t = 1 hours), concentration of the drug = 750 mg

y=1000(b)^t

750=1000(b)^1

b=\frac{750}{1000}

b=\frac{3}{4}

Therefore, equation will be,

y=1000(\frac{3}{4})^t

8 0
3 years ago
a rectangle pool is 9 ft wide. the pool has an area of 117 square feet. what is the perimeter of the pool?
Softa [21]
9*13=117
(9*2)+(13*2)=44
44 feet
6 0
3 years ago
Read 2 more answers
Find the three angles of a triangle if the sum of the first angle and twice the second equals the third and, and if four times t
Anna71 [15]

Answer:

First Angle = 45°

Second Angle = 30°

Third Angle = 105°  

Step-by-step explanation:

First angle + 2(Second angle ) = Third Angle

4(second angle) = Third Angle + 15°

or, Third angle = 4(second angle)  - 15° ...(1)

⇒First angle + 2(Second angle )  = 4(second angle)  -  15°

or, First angle  = 2(second angle)  -  15° ... (2)

Now by ANGLE SUM PROPERTY of a triangle:

First angle+ Second angle + Third Angle  = 180°

Now, putting the values of (1) , (2) in above expression,

{2(Second angle)  -  15° } +  Second angle +{ 4(second angle)  - 15°} = 180°

is the required equation.

or, 7(Second angle) - 30° = 180°

or, 7(Second angle)  =   30° +   180°  =  210°

⇒ Second angle = 210°/ 7  = 30°

Now, First angle  = 2(second angle)  -  15°

                              = (2 x 30°)  - 15°  = 45°

and, Third angle = 4(second angle)  - 15°

                            = 4 x 30°  - 15°  =  120 - 15°  = 105°

5 0
4 years ago
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