Let's begin by listing out the information given to us:
8 am
airplane #1: x = 80870 ft, v = -450 ft/ min
airplane #2: x = 5000 ft, v = 900ft/min
1.
We must note that the airplanes are moving at a constant speed. The equation for the airplanes is given by:
2.
We equate equations 1 & 2 to get the time both airlanes will be at the same elevation. We have:
3.
The elevation at that time (when the elevations of the two airplanes are the same) is given by substituting the value of time into equations 1 & 2. We have:
The x-intercept represents the points in which the quadratic function passes through the x-axis. The maximum value represents the ordered pair with the highest range(y-value).
Interval increasing: (Negative Infinity-10)
Interval Decreasing: (10-Negative Infinity)
Part B: 8/5
Note: I am assuming the scale factor of the graph is 2.
Answer:
second option
G(3 , -4) ; H(8 , 1)
Step-by-step explanation:
For the line GH to be a median, the point G must have the intermediate value at x and at y between points A and B, and the point H must have the intermediate value at x and at y between points A and B
G = (Ax + Bx)/2 , (Ay + By)/2
G = (3 + 3)/2 , (-9 + 1)/2
G = 6/2 , -8/2
G = (3 , -4)
H = (Cx + Bx)/2 , (Cy + By)/2
H = (13 + 3)/2 , (1 + 1)/2
H = 16/2 , 2/2
H = (8 , 1)
This is because for a medium to be the point p has to be right in the middle of the other 2 vertices
Looking at the graph, we'll notice that there is a local maximum at x=0 and it looks similar on both sides of the y axis, therefore making it symmetric around the y axis given the options
