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lions [1.4K]
3 years ago
6

A cat had a litter of 5 kittens. If each sex is equally likely, what is the probability that 3 or less were female kittens? 0.31

25 0.500 0.8125 0.2500
Mathematics
2 answers:
Naddik [55]3 years ago
8 0

Answer:

Probability of 3 or less = 0.8125.

Step-by-step explanation:

This is a binomial probability distribution.

Prob(0 females) =  5C0(1/2)^5 = 0.03125

Prob(1 female) = 5C1 (1/2)^5 = 0.15625

Prob(2 females) = 5C2(1/2)^5 = 0.3125

Prob(3 females) = 5C3(1/2)^5 = 0.3125

Adding these we get 0.8125.

Dennis_Churaev [7]3 years ago
6 0

Answer:

WHAT IS THIS QUESTION AHHH BUT 03125

Step-by-step explanation:

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Box 1 contains 3 blue and 5 red balls, whereas Box 2 contains 2 blue and 4 red ball. A ball is randomly chosen from Box 1 and th
muminat

Answer:

0.32

Step-by-step explanation:

Let A be the event that the transferred ball was blue.

B be the event that the red ball is selected from box 2

C be the event that the transferred ball was red

Then:

P(A) be the probability that the transferred ball was blue, which is 3/8

P(C) be the probability that the transferred ball was red, which is 5/8

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P(B|C) is the probability that selected ball is red, given that the transferred ball was red, which is 5/7

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P(B) = P(B|A)P(A) + P(B|C)P(C)

P(B) = \frac{4}{7}\frac{3}{8} + \frac{5}{7}\frac{5}{8}

P(B) = \frac{3}{14} + \frac{25}{56} = \frac{37}{56}

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P(A|B) = \frac{P(B|A)P(A)}{P(B)} = \frac{\frac{4}{7}*\frac{3}{8}}{\frac{37}{56}} = \frac{3}{14}\frac{56}{37} = \frac{12}{37} = 0.324

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Step-by-step explanation:

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