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3 years ago

The function f(x) is graphed below. what is f(2)-f(-1)?

Mathematics

1 answer:

telo118 [61]3 years ago

7 0

photmath, alcaicion par aresolvr perbolmeas mtemataicso ,ect a

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The four swimmers listed in the table are trying out for the swim team. Two will make the team. How many different combinations

ratelena [41]

Number of possible combinations = (4x3) ÷ 2 = 6

Answer: There are 6 possible combinations.

8 0

3 years ago

Find any 3 (x,y) pairs that are solutions for the equation 2x-5y=10 . Show your work

Alla [95]

Answer:

(0,-2), (5,0) and (10,2).

Step-by-step explanation:

Given equation is $2x-5y=10$ .

Now we need to find 3 pairs of solutions in (x,y) form for the given equation.

As $2x-5y=10$ is a linear equation so we are free to pick any number for x like x=0, 5, 10

Plug x=0 into $2x-5y=10$ , we get:

$2(0)-5y=10$

$0-5y=10$

$-5y=10$

$y=\frac{10}{-5}$

$y=-2$

Hence first solution is (0,-2)

We can repeat same process with x=5 and 10 to get the other solutions.

Hence final answer is (0,-2), (5,0) and (10,2).

5 0

3 years ago

Read 2 more answers

Can someone help me please

Sergeeva-Olga [200]

Answer:

Step-by-step explanation:

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3 years ago

Read 2 more answers

Find the solution of the following equation whose argument is strictly between 270^\circ270 ∘ 270, degree and 360^\circ360 ∘ 360

Natasha2012 [34]

$\rightarrow z^4=-625\\\\\rightarrow z=(-625+0i)^{\frac{1}{4}}\\\\\rightarrow x+iy=(-625+0i)^{\frac{1}{4}}\\\\ x=r \cos A\\\\y=r \sin A\\\\r \cos A=-625\\\\ r \sin A=0\\\\x^2+y^2=625^{2}\\\\r^2=625^{2}\\\\|r|=625\\\\ \tan A=\frac{0}{-625}\\\\ \tan A=0\\\\ A=\pi\\\\\rightarrow z= [625(\cos (2k \pi+pi) +i \sin (2k\pi+ \pi)]^{\frac{1}{4}}\\\\k=0,1,2,3,4,....\\\\\rightarrow z=(625)^{\frac{1}{4}}[\cos \frac{(2k \pi+pi)}{4} +i \sin \frac{(2k\pi+ \pi)}{4}]$

$\rightarrow z_{0}=(625)^{\frac{1}{4}}[\cos \frac{pi}{4} +i \sin \frac{\pi)}{4}]\\\\\rightarrow z_{1}=(625)^{\frac{1}{4}}[\cos \frac{3\pi}{4} +i \sin \frac{3\pi}{4}]\\\\ \rightarrow z_{2}=(625)^{\frac{1}{4}}[\cos \frac{5\pi}{4} +i \sin \frac{5\pi}{4}]\\\\ \rightarrow z_{3}=(625)^{\frac{1}{4}}[\cos \frac{7\pi}{4} +i \sin \frac{7\pi}{4}]$

Argument of Complex number

Z=x+iy , is given by

If, x>0, y>0, Angle lies in first Quadrant.

If, x<0, y>0, Angle lies in Second Quadrant.

If, x<0, y<0, Angle lies in third Quadrant.

If, x>0, y<0, Angle lies in fourth Quadrant.

We have to find those roots among four roots whose argument is between 270° and 360°.So, that root is

$\rightarrow z_{2}=(625)^{\frac{1}{4}}[\cos \frac{5\pi}{4} +i \sin \frac{5\pi}{4}]$

5 0

3 years ago

At a school trivia competition, contestants can answer two kinds of questions: easy questions and hard

lorasvet [3.4K]

Answer:

Step-by-step explanation:

so 8*5 is 40 which leaves 39 points to be accounted for.

39/3 is 13 (easy questions)

8+13=21 which is the amount of questions Chantrea answered correctly so yee

5 0

3 years ago