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jeyben [28]
3 years ago
9

ANswer please! Brainliest!!

Mathematics
1 answer:
andreyandreev [35.5K]3 years ago
5 0

Answer:

b and c

Step-by-step explanation:

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8x^2*3xy

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Help please really need it fast :)
Serga [27]

Answer:

.4 x .9

Step-by-step explanation:

5 0
3 years ago
One sample has a mean of and a second sample has a mean of . The two samples are combined into a single set of scores. What is t
Murrr4er [49]

Answer:

a) For this case we can use the definition of weighted average given by:

M = \frac{ \bar X_1 n_1 + \bar X_2 n_2}{n_1 +n_2}

And if we replace the values given we have:

M = \frac{8*4 + 16*4}{4+4}= 12

b) M = \frac{8*3 + 16*5}{3+5}= 13

c) M = \frac{8*5 + 16*3}{5+3}= 11

Step-by-step explanation:

Assuming the following question: "One sample has a mean of M=8 and a second sample has a mean of M=16 . The two samples are combined into a single set of scores.

a) What is the mean for the combined set if both of the original samples have n=4 scores "

For this case we can use the definition of weighted average given by:

M = \frac{ \bar X_1 n_1 + \bar X_2 n_2}{n_1 +n_2}

And if we replace the values given we have:

M = \frac{8*4 + 16*4}{4+4}= 12

b) what is the mean for the combined set if the first sample has n=3 and the second sample has n=5

Using the definition we have:

M = \frac{8*3 + 16*5}{3+5}= 13

c) what is the mean for the combined set if the first sample has n=5 and the second sample has n=3

Using the definition we have:

M = \frac{8*5 + 16*3}{5+3}= 11

7 0
3 years ago
X^2-y^2=3y in polar form
Assoli18 [71]

Answer:

Step-by-step explanation:

put x=r cos θ

y=r sin θ

r²cos²θ-r²sin²θ=3rsin θ

r²(cos²θ -sin²θ)=3r sin θ

r²cos 2θ=3rsinθ

r cos 2θ=3 sin θ

r=3sec 2θ sin θ

5 0
3 years ago
What’s the answer and how do I solve it?
Levart [38]
A solution is where the graph crosses the x axis (when y=0). Since the graph never touched the x axis, there is no solution.
6 0
3 years ago
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