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Flura [38]
3 years ago
6

98464 rounded to the nearest ten thousand?​

Mathematics
2 answers:
mestny [16]3 years ago
6 0

Answer:10,000

Step-by-step explanation:Just round the 9

dusya [7]3 years ago
4 0

Answer:

100000

Step-by-step explanation:

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Can someone help with this please?
sleet_krkn [62]

Answer:

y = x - 3

Step-by-step explanation:

From the table attached,

Scatter plot given in the graph is correct.

Let the equation of the line passing from a point (x', y') is,

y - y' = m(x - x')

m = slope

Slope of the line passing through two points (x_2,y_2) and (x_1,y_1) is given by,

m = \frac{y_2-y_1}{x_2-x_1}

Therefore, slope of the line passing through the points (11, 8) and (12, 9) will be,

m = \frac{(9-8)}{(12-11)} =1

Therefore, equation of the line passing through (11, 8) will be,

y - 8 = 1(x - 11)

y = x - 11 + 8

y = x - 3

7 0
3 years ago
The next number in the arithmetic sequence 15, 22, 29, is: <br><br>A) 34<br>B) 35<br>C) 36<br>D) 37​
harkovskaia [24]
ANSWER: C) 36
EXPLANATION: +7 is the sequence
4 0
2 years ago
Simplify the expression:<br> -12 - 4x + 9 + -10 + 8x
Ann [662]

Answer:

Step-by-step explanation:

4x-13

4 0
2 years ago
Read 2 more answers
At the sewing store ashly bought a bag of mixed buttons she got 25 buttons in all 5 of the buttons were large what percentage of
iren [92.7K]

Answer:

20%

Step-by-step explanation:

You have to do 5/25, giving you 20%.

8 0
3 years ago
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Dos motos, A y B, toman la salida en una carrera de 90 km. La moto A realiza el recorrido con una velocidad media inferior en 20
aleksandr82 [10.1K]

Answer:

motorcycle A: 180 km/h

motorcycle B: 200 km/h

Step-by-step explanation:

To solve this question we need to write a system of equations for A and B, using the equation:

distance = speed * time

The speed of A is 20 less than the speed of B, so:

speedA = speedB - 20

And the time A traveled is 3 minutes (0.05 hours) more than B's time, so:

timeA = timeB + 0.05

Then, using the distance equation, we have that:

distanceB = speedB * timeB

90 = speedB * timeB

distanceA = speedA * timeA

90 = (speedB - 20) * (timeB + 0.05)

90 = speedB * timeB + 0.05 * speedB - 20*timeB - 1

90 = 90 + 0.05 * speedB - 20*timeB - 1

20*timeB = 0.05 * speedB - 1

timeB = (speedB - 20)/400

using this timeB in the distance equation, we have:

90 = speedB * (speedB - 20)/400

90 * 400 = speedB^2 - 20*speedB

speedB^2 - 20*speedB - 36000 = 0

Solving this quadratic equation, we have speedB = 200 km/h

And the speedA is:

speedA = speedB - 20 = 200 - 20 = 180 km/h

6 0
2 years ago
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