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2 years ago

Secant and Tangent Angles in circles. Solve for x.

Mathematics

2 answers:

rodikova [14]2 years ago

5 0

Answer: x = 0.6

Step-by-step explanation: i dont want to explain the math i did because it already took up too much time. but im pretty sure that its the right answer. after i got 0.6, i plugged it back into the equation to check and it worked

poizon [28]2 years ago

3 0

Answer:

x = 1

Step-by-step explanation:

5x + 17 = 1/2[(73x + 5) - (23x - 5)]

5x + 17 = 1/2[37x + 5 - 23x + 5]

5x + 17 = 1/2[14x + 10]

5x + 17 = 1/2 * 2(7x + 5)

5x + 17 = 7x + 5

5x - 17x = 5 - 17

-12x = - 12

x = - 12/-12

x = 1

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The scale of a map uses 10 cm for 30 km.<br> How many centimeters does it use for 9 km?<br> +

xxTIMURxx [149]

Answer:

3 km

Step-by-step explanation:

30 divided by 10 is 3.

9 divided by 3 is 3.

Therefore, your answer is 3.

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2 years ago

74% of freshmen entering public high schools in 2006 graduated with their class in 2010. A random sample of 81 freshmen is selec

Assoli18 [71]

Answer: Probability that the proportion of students who graduated is greater than 0.743 is P = 0.4755

Step-by-step explanation:

Given that,

Probability of freshmen entering public high schools in 2006 graduated with their class in 2010, p = 0.74

Random sample of freshman, n = 81

Utilizing central limit theorem,

$P(\hat{p}$

So,

$(P(\hat{p}>0.743) = P(Z>0.743 - \frac{0.74}{\sqrt{\frac{0.74(1-0.74)}{81} } } )$

= P( Z > 0.0616)

= 0.4755 ⇒ probability that the proportion of students who graduated is greater than 0.743.

7 0

2 years ago

Trigonometry and trigonometric functions

zaharov [31]

Answer:

The trigonometric functions include the following 6 functions: sine, cosine, tangent, cotangent, secant, and cosecant. For each of these functions, there is an inverse trigonometric function. The trigonometric functions can be defined using the unit circle.

Step-by-step explanation:

6 0

2 years ago

If tanA=a <br>then find sin4A-2sin2A/ sin4A+2sin2A

anygoal [31]

Answer:

The value of the given expression is

$\frac{sin4A-2sin2A}{sin4A+2sin2A}=-a^2$

Step by step Explanation:

Given that $tanA=a$

To find the value of $\frac{sin4A-2sin2A}{sin4A+2sin2A}$

Let us find the value of the expression :

$\frac{sin4A-2sin2A}{sin4A+2sin2A}=\frac{2cos2Asin2A-2sin2A}{2cos2Asin2A+2sin2A}$ ( by using the formula $sin2A=2cosAsinA$ here A=2A)

$=\frac{2sin2A(cos2A-1)}{2sin2A(cos2A+1)}$

$=\frac{(cos2A-1)}{(cos2A+1)}$

$=\frac{(-(1-cos2A))}{(1+cos2A)}$ (using $sin^2A+cos^2A=1$ here A=2A)

$=\frac{-(sin^2A+cos^2A-(cos^2A-sin^2A))}{sin^2A+cos^2A+(cos^2A-sin^2A)}$ (using $cos2A=cos^2A-sin^2A$ here A=2A)

$=\frac{-(sin^2A+cos^2A-cos^2A+sin^2A)}{sin^2A+cos^2A+(cos^2A-sin^2A)}$

$=\frac{-(sin^2A+sin^2A)}{cos^2A+cos^2A}$

$=\frac{-2sin^2A}{2cos^2A}$

$=-\frac{sin^2A}{cos^2A}$

$=-tan^2A$ ( using $tanA=\frac{sinA}{cosA}$ here A=2A )

$=-a^2$ (since tanA=a given )

Therefore $\frac{sin4A-2sin2A}{sin4A+2sin2A}=-a^2$

6 0

2 years ago

Determine if the conclusion of salad. Give a thorough explanation of your answer. Given segment AC is perpendicular to segment c

serious [3.7K]

The given conclusion that ABCD is a square is not valid.

Given that, AC⊥BD and AC≅BD.

We need to determine if the given conclusion is valid.

<h3>What are the properties of squares?</h3>

A square is a closed figure with four equal sides and the interior angles of a square are equal to 90°. A square can have a wide range of properties. Some of the important properties of a square are given below.

A square is a quadrilateral with 4 sides and 4 vertices.
All four sides of the square are equal to each other.
The opposite sides of a square are parallel to each other.
The interior angle of a square at each vertex is 90°.
The diagonals of a square bisect each other at 90°.
The length of the diagonals is equal.

Given that, the diagonals of a quadrilateral are perpendicular to each other and the diagonals of a quadrilateral are equal.

Now, from the properties of a square, we understood that the diagonals of a square are perpendicular to each other and the diagonals of a square are equal.

So, the given quadrilateral can be a square. But only with these two properties can not conclude the quadrilateral is a square.

Therefore, the given conclusion that ABCD is a square is not valid.

To learn more about the properties of a square visit:

brainly.com/question/20377250.

#SPJ1

4 0

1 year ago

Secant and Tangent Angles in circles. Solve for x.​

Secant and Tangent Angles in circles. Solve for x.