3 years ago

Secant and Tangent Angles in circles. Solve for x.

Mathematics

2 answers:

rodikova [14]3 years ago

5 0

Answer: x = 0.6

Step-by-step explanation: i dont want to explain the math i did because it already took up too much time. but im pretty sure that its the right answer. after i got 0.6, i plugged it back into the equation to check and it worked

poizon [28]3 years ago

3 0

Answer:

x = 1

Step-by-step explanation:

5x + 17 = 1/2[(73x + 5) - (23x - 5)]

5x + 17 = 1/2[37x + 5 - 23x + 5]

5x + 17 = 1/2[14x + 10]

5x + 17 = 1/2 * 2(7x + 5)

5x + 17 = 7x + 5

5x - 17x = 5 - 17

-12x = - 12

x = - 12/-12

x = 1

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Given directed line segment PR below, find the coordinates of Q on PR

g100num [7]

Answer:

$(\frac{4}{3},-3)$

Step-by-step explanation:

The location of a point O(x, y) which divides line segment AB in the ratio a:b with point A at ( $x_1,y_1$ ) and B( $x_2,y_2$ ) is given by the formula:

$x=\frac{a}{a+b}(x_2-x_1)+x_1\\ \\y=\frac{a}{a+b}(y_2-y_1)+y_1$

From the graph, the location of the point is P(2, 5), R(1, -7). Let point Q be (x, y) which divides PR in ratio 2:1. Coordinates of point Q is at:

$x=\frac{a}{a+b}(x_2-x_1)+x_1=\frac{2}{2+1}(1-2)+2=\frac{2}{3}(-1)+2=\frac{4}{3} \\ \\y=\frac{a}{a+b}(y_2-y_1)+y_1=\frac{2}{2+1}(-7-5)+5= \frac{2}{3}(-12)+5=-3$