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2 years ago

PLEASE HELP with question 7! BRAINLIEST to correct answer!!!!

Mathematics

2 answers:

Aneli [31]2 years ago

7 0

Answer: rasie 13 to 3/4

Step-by-step explanation:

Lorico [155]2 years ago

3 0

Raise 13 to 3/4 if this helps you

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2 years ago

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Help please! 15 pts!

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Answer: attached below

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3 years ago

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Solve for x in the diagram.

Kazeer [188]

It is a right triangle so,

a² + b² = x²
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3 years ago

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For what positive values of k does the function y=sin(kt) satisfy the differential equation y''+144y=0 ?

lina2011 [118]

Answer:

The positive value of k that the function y = sin(kt) satisfies the differential equation y'' + 144y = 0 is +12

Step-by-step explanation:

To determine the positive values of k that the function y = sin(kt) satisfy the differential equation y''+144y=0.

First, we will determine y''.

From y = sin(kt)

y' = $\frac{d}{dt}(y)$

y' = $\frac{d}{dt}(sin(kt))\\$

y' = kcos(kt)

Now for y''

y'' = $\frac{d}{dt}(y')$

y'' = $\frac{d}{dt}(kcos(kt))$

y'' = $-k^{2}sin(kt)$

Hence, the equation y'' + 144y = becomes

$-k^{2}sin(kt)$ + $144(sin(kt))$ $= 0$

$(144 - k^{2})(sin(kt)) = 0$

$(144 - k^{2})= 0$

∴ $k^{2} = 144\\$

$k =$ ± $\sqrt{144}\\$

$k =$ ± $12$

∴ $k = +12$ or $-12$

Hence, the positive value of k that the function y = sin(kt) satisfies the differential equation y'' + 144y = 0 is +12

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3 years ago

Find the approximate perimeter of pentagon ABCDE plotted below.

meriva

Answer: 32.5

Step-by-step explanation:

This is the answer on Khan Acadamy

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2 years ago

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