H = 6 in
V=bh
H=v/b
H=36/6
H=6
Answer:
might be 3
Step-by-step explanation:
Answer:
Solution given:
BD=35ft
AC=43ft
AB=8ft
EF=33-8=25ft
AE=26ft
Now
area of right angled triangle ∆AEF
=½(EF*AE)=½(25×25)=312.5ft²
area of parallel trapezoid=½AB(BD+AC)
=½*8(35+43)=312ft²
<u>So</u>
<u>Area</u><u> </u><u>of</u><u> </u><u>polygon</u><u> </u><u>:</u><u> </u><u>3</u><u>1</u><u>2</u><u>.</u><u>5</u><u>+</u><u>3</u><u>1</u><u>2</u><u>=</u><u>6</u><u>2</u><u>4</u><u>.</u><u>5</u><u>f</u><u>t</u><u>²</u><u> </u><u>is</u><u> </u><u>a</u><u> </u><u>required</u><u> </u><u>answer</u><u>.</u>
Hi, I'd be glad to help you with this equation.
The answer is (33/43)
Hope this helps.
Have a great day!
Answer:
Remember that the slope of perpendicular lines are negative reciprocals of each other.
Step-by-step explanation:
y = 1 - 2x the slope is -2 the value of the x term.
So the slope of the new line using point (- 1, 2) is 1/2.
Now use y = mx + b where y = -1, x = 2, and m = 1/2 .
y = mx + b
-1 = 1/2(2) + b solve for "b", the y-intersect
-1 = 1 + b
-2 = b
The line that is perpendicular to y = 1 - 2x is y = 1/2x - 2