Find the mean median and mode 15,3, 11, 15,1,14,7,2,1,1,2

Mathematics

2 answers:

mote1985 [20]3 years ago

5 0

Well, the mode is what's most often and that's:
1
the mean is:<span>
</span>6.5454545454545
the median is:
3

algol [13]3 years ago

5 0

Answer: Median = 3, Mean = 6.45, Mode = 1.

Step-by-step explanation:

Since we have given that

15,3, 11, 15,1,14,7,2,1,1,2

As we know the formula for "Mean" :

$Mean=\frac{15+3+11+15+1+14+7+2+1+1+2}{11}\\\\Mean=6.45$

Mean = 6.45

Similarly, we know the formula for "Median":

First we write it in ascending order:

1,1,1,2,2,3,7,11,14,15,15

$Me=(\frac{n+1}{2})^{th}\\Me=\frac{11+1}{2}^{th]\\Me=\frac{12}{2}^{th]\\Me=6^{th}\\Me=3$

Median = 3

Mode is the number which has occurred mostly, has the highest frequency.

Mode = 1

Hence, Median = 3, Mean = 6.45, Mode = 1.

You might be interested in

A 1.5-mm layer of paint is applied to one side of the following surface. Find the approximate volume of paint needed. Assume tha

Mariulka [41]

Answer:

V = 63π / 200 m^3

Step-by-step explanation:

Given:

- The function y = f(x) is revolved around the x-axis over the interval [1,6] to form a spherical surface:

y = √(42*x - x^2)

- The surface is coated with paint with uniform layer thickness t = 1.5 mm

Find:

The volume of paint needed

Solution:

- Let f be a non-negative function with a continuous first derivative on the interval [1,6]. The Area of surface generated when y = f(x) is revolved around x-axis over the interval [1,6] is:

$S = 2*\pi \int\limits^a_b { [f(x)*\sqrt{1 + f'(x)^2} }] \, dx$

- The derivative of the function f'(x) is as follows:

$f'(x) = \frac{21-x}{\sqrt{42x-x^2} }$

- The square of derivative of f(x) is:

$f'(x)^2 = \frac{(21-x)^2}{42x-x^2 }$

- Now use the surface area formula:

$S = 2*\pi \int\limits^6_1 { [\sqrt{42x-x^2} *\sqrt{1 + \frac{(21-x)^2}{42x-x^2 } }] \, dx\\\\S = 2*\pi \int\limits^6_1 { [\sqrt{42x-x^2+(21-x)^2} }] \, dx\\\\S = 2*\pi \int\limits^6_1 { [\sqrt{42x-x^2+441-42x+x^2} }] \, dx\\\\S = 2*\pi \int\limits^6_1 { [\sqrt{441} }] \, dx\\S = 2*\pi \int\limits^6_1 { 21} \, dx\\\\S = 42*\pi \int\limits^6_1 { dx} \,\\\\S = 42*\pi [ 6 - 1 ]\\\\S = 42*5*\pi \\\\S = 210\pi$