First multiply both sides by 7
Your equation now looks like this:
x-28=0
Now move the constant to the other side causing it to change signs
The negative now becomes a positive
x=28
Now you are left with your answer:
x=28
Hope this helps! :3
Answer:
B) -2x+2y=-2
Step-by-step explanation:
we have
----> equation A
----> equation B
Solve the system by graphing
Remember that the solution of the system of equations is the intersection point both graphs
using a graphing tool
The solution is the point (6,5)
see the attached figure
Remember that
If a equation is added to the system so that the solution does not change, then the solution of the system must be a solution of the equation added
<u><em>Verify each case</em></u>
The solution of the system is (6,5)
substitute the value of x and the value of y in each equation
case A) x-y=2
6-5=2
1=2 ----> is not true
therefore
This equation can't be added to the system
case B) -2x+2y=-2
-2(6)+2(5)=-2
-12+10=-2
-2=-2 ----> is true
therefore
This equation can be added to the system
case C) 3x+y=20
3(6)+5=20
18+5=20
23=20 ----> is not true
therefore
This equation can't be added to the system
case D) x+2y=18
5+2(6)=18
5+12=18
17=18 ----> is not true
therefore
This equation can't be added to the system
Answer:
X = 2
Y=7
Step-by-step explanation:
The explanation is in the pictures
Answer:
The form of the sum of cubes identity is a³ + b³ = (a + b)(a² - ab + b²) ⇒ A
Step-by-step explanation:
To find the form of the sum of cubes identity ⇒ x³ + y³
- find the cube root of each one and add them in a small bracket ⇒ (x + y)
- square the first term in the small bracket and put it as the 1st term in a big bracket ⇒ (x² ....)
- put (-) after the 1st term ⇒ (x² - .....)
- multiply the 1st and 2nd term in the small bracket and put the product as the 2nd term in the big bracket ⇒ (x² - xy .....)
- square the 2nd term in the small bracket and add it to the terms of the big bracket ⇒ (x² - xy + y²)
Then the form of the sum of cubes identity is x³ + y³ = (x + y)(x² - xy + y²)
∵ a³ + b³ is a sum of two cubes
→ By using the same steps above
∵
= a and
= b
∴ The small bracket is (a + b)
∵ Square a = a² and square b = b²
∵ a × b = ab
∴ The big bracket is (a² - ab + b²)
∴ The form of the sum of cubes identity is a³ + b³ = (a + b)(a² - ab + b²)