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3 years ago

Help plzzzz The minimum value os 58 The median value is 82 The third quartile is 58

Mathematics

2 answers:

iragen [17]3 years ago

4 0

Answer:

It is a box

Step-by-step explanation:

IT's a box ,because I had to put a stick in the box

andriy [413]3 years ago

3 0

This just labels the box plot hope this helps

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How do you solve 12+5x = 18+3x

guajiro [1.7K]

Answer: x = 3

Step-by-step explanation:Simplifying

12 + 5x = 18 + 3x

Solving

12 + 5x = 18 + 3x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3x' to each side of the equation.

12 + 5x + -3x = 18 + 3x + -3x

Combine like terms: 5x + -3x = 2x

12 + 2x = 18 + 3x + -3x

Combine like terms: 3x + -3x = 0

12 + 2x = 18 + 0

12 + 2x = 18

Add '-12' to each side of the equation.

12 + -12 + 2x = 18 + -12

Combine like terms: 12 + -12 = 0

0 + 2x = 18 + -12

2x = 18 + -12

Combine like terms: 18 + -12 = 6

2x = 6

Divide each side by '2'.

x = 3

Simplifying

x = 3

6 0

3 years ago

Read 2 more answers

OMG GUYS HELP ASAP!!!! THIS IS MY HW ALSO!

natka813 [3]

One point: draw the line a bit lower such that it touches the circle. A line from the center of the circle to the line will be perpendicular to it.

Two points: draw the line somewhere through the circle. There will be two intersection points.

Three points: can't be done.

3 0

3 years ago

Suppose two events A and B are mutually exclusive, with P(A) ≠ 0 and P(B) ≠ 0. By working through the following steps, you'll se

DanielleElmas [232]

Answer with Step-by-step explanation:

We are given that two events A and B are mutually exclusive.

$A\cap B=\phi$

$P(A\cap B)=0$

$P(A)\neq 0$

$P(B)\neq 0$

a.For mutually exclusive events,

$P(A/B)=\frac{P(A\cap B)}{P(B)}=\frac{0}{P(A)}=0$

Therefore, event A can not occurred if event B has occurred because two events can not occur together.

Answer:No, by definition mutually exclusive events cannot occur together.

b.When two events are independent

Then , $P(A\cap B)=P(A)\cdot P(B)$

$P(A/B)=\frac{P(A)\cdot P(B)}{P(B)}=P(A)$

If two events are mutually exclusive then

$P(A\cap B)=0$

Then , $P(A/B)=0$

Therefore, $P(A/B)\neq P(A)$

Hence, we can concluded that events A and B are not independent if they are mutually exclusive.

Answer:Yes, $P(A/B)\neq P(A)$

7 0

3 years ago

Miguel and three of his friends went to the movies. They originally had a total of $40. Each boy had the same amount of money an

Alenkasestr [34]

Answer:

The money each boy had after buying his ticket is $2.50.

Step-by-step explanation:

Given:

Miguel and three of his friends went to the movies. They originally had a total of $40. Each boy had the same amount of money and spent $7.50 on a ticket.

Now, to find the money each boy had after buying his ticket.

Let the money each boy had after buying his ticket be $x.$