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vekshin1
3 years ago
11

What is the mixed number3 3/8 as a fraction

Mathematics
1 answer:
cluponka [151]3 years ago
7 0

Answer:   Mixed Number to Fraction

Mixed Numbers to Improper Fraction

<em>Mixed Numbers Improper Fraction</em>

3 3/4                      15/4

3 3/8                      27/8

3 8/9                      35/9

<em><u>Hope this helps!!</u></em>

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7 0
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here is an equation that is true for all values of x:5(x+2)=5x+10. Elena saw this equation and says she can tell 20(x+2)=4(5x+10
Trava [24]

Elena is wrong, because the two sides of equation are not equal for all values of x

Step-by-step explanation:

An equation of x is true for all values of x when the left hand side

is equal to the right hand side

To prove that an equation is true for all values of x do that

  • Simplify the left hand side and the right hand side
  • Solve the equation to find x, you will find the x in the left hand side is equal to x in the right hand side, so they canceled each other, and the numerical terms in the two sides equal each other, that means the equation is true for any values of x

Lets check that with given equation 5(x + 2) = 5x + 10

∵ 5(x + 2) = 5x + 10

- Simplify the left hand side

∵ 5(x) + 5(2) = 5x + 10

∴ 5x + 10 = 5x + 10

- Subtract 5x from both sides

∴ 10 = 10

∵ L.H.S = R.H.S

∴ The equation is true for all values of x

Lets do that with Elena's equation

∵ 20(x + 2) = 4(5x + 10) + 31

- Simplify the two sides of the equation

∵ 20(x) + 20(2) = 4(5x) + 4(10) + 31

∴ 20x + 40 = 20x + 40 + 31

- Add like terms in the right hand side

∴ 20x + 40 = 20x + 71

- Subtract 20x from both sides

∴ 40 = 71 ⇒ and that not true

∵ L.H.S ≠ R.H.S

∴ The equation is not true for all values of x

Elena is wrong, because the two sides of equation are not equal for all values of x

Learn more:

You can learn more about the equations in brainly.com/question/11306893

#LearnwithBrainly

5 0
3 years ago
38 POINTS!!!!
3241004551 [841]

Hello from MrBillDoesMath!

Answer:

Perimeter = 60

Height =  18/5

Discussion:

The diagonals of a rhombus  bisect each other at right angles. So a rhombus can be viewed as the union of 4 congruent right triangles, each with legs (1/2)*18 = 9 and (1/2) *24 = 12. See attachment. This gives a hypotenuse length of 15 so the Perimeter = 4 *c = 60.

The height ( = altitude) of a rhombus is

            = area                    / length of base

            = (1/2)  ( (18) * 24) /c

            = (1/2) ( 18 * 24) / 60

            = 18/5

Thank you,

MrB

7 0
3 years ago
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