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andreyandreev [35.5K]

2 years ago

12

What is Variable for m+3=-m -1

1 answer:

CaHeK987 [17]2 years ago

3 0

You’re answer should be m= -2

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This is the choices <br> 88<br> 70<br> 110<br> 120

s344n2d4d5 [400]

Answer:

110

Step-by-step explanation:

Y and X have to equal 180

70+x+180

=110

7 0

2 years ago

Read 2 more answers

Express the quotient of z1 and z2 in standard form given that <img src="https://tex.z-dn.net/?f=z_%7B1%7D%20%3D%20-3%5Bcos%28%5C

Lesechka [4]

Answer:

Solution : $-\frac{3}{4}-\frac{3}{4}i$

Step-by-step explanation:

$-3\left[\cos \left(\frac{-\pi }{4}\right)+i\sin \left(\frac{-\pi \:}{4}\right)\right]\:\div \:2\sqrt{2}\left[\cos \left(\frac{-\pi \:\:}{2}\right)+i\sin \left(\frac{-\pi \:\:\:}{2}\right)\right]$

Let's apply trivial identities here. We know that cos(-π / 4) = √2 / 2, sin(-π / 4) = - √2 / 2, cos(-π / 2) = 0, sin(-π / 2) = - 1. Let's substitute those values,

$\frac{-3\left(\frac{\sqrt{2}}{2}-\frac{\sqrt{2}}{2}i\right)}{2\sqrt{2}\left(0-1\right)i}$

= $-3\left(\frac{\sqrt{2}}{2}-\frac{\sqrt{2}}{2}i\right)$ ÷ $2\sqrt{2}\left(0-1\right)i$

= $3\left(-\frac{\sqrt{2}i}{2}+\frac{\sqrt{2}}{2}\right)$ ÷ $-2\sqrt{2}i$

= $\frac{3\left(1-i\right)}{\sqrt{2}}$ ÷ $2\sqrt{2}i$ = $-3-3i$ ÷ $4$ = $-\frac{3}{4}-\frac{3}{4}i$

As you can see your solution is the last option.

3 0

2 years ago

Solve for x when <img src="https://tex.z-dn.net/?f=x%5E%7Byz%7D%20%3Dy%5E%7B2%7D" id="TexFormula1" title="x^{yz} =y^{2}" alt="x^

Assoli18 [71]

The value of x in x^yz = y^2 is $x = \sqrt[yz]{y^2}$

<h3>How to solve for x?</h3>

The equation is given as:

x^yz = y^2

Rewrite the equation properly as follows

$x^{yz} = y^2$

Take the yz root of both sides

$\sqrt[yz]{x^{yz}} = \sqrt[yz]{y^2}$

Apply the law of indices

$x^{\frac{yz}{yz}} = \sqrt[yz]{y^2}$

Divide yz by yz

$x = \sqrt[yz]{y^2}$

Hence, the value of x in x^yz = y^2 is $x = \sqrt[yz]{y^2}$

Read more about equations at:

brainly.com/question/2972832

#SPJ1

7 0

1 year ago

Read 2 more answers

A watercolor painting is 24 inches long by 11 inches wide. Ramon makes a border around the watercolor painting by making a mat t

sergeinik [125]

Given: It is given that the length of the painting is 24 inches and the width is 11 inches.

To find: Area of the mat

Solution:

The watercolor painting is 24 inches long by 11 inches wide.

So, the area of the painting is:

$\text{Area of painting}=l\times b$

$\text{Area of painting}=24\times 11$

$\text{Area of painting}=264 \text{ in}^2$

The length of painting with mat is = 24 in + 3 in + 3 in = 30 in

The width of painting with mat = 11 in + 3 in + 3 in = 17 in

$\text{Area of painting with mat}=30\times 17$

$\text{Area of painting with mat}=510 \text{ in}^2$

Now to calculate the area of mat subtracts the area of painting from the area of the mat.

$\text{Area of mat}=\text{Area of painting with mat}-\text{Area of painting}\\$

$\text{Area of mat}=510-264$

$\text{Area of mat}=246 \text{ in}^2$

Hence, the area of the mat is 246 in².

6 0

2 years ago

A farmer has a rectangular field that is 100 yards long by 20 yards wide. What is the total area of the field?

sveta [45]

The area of the field is equal to the area of rectangular
a = l × w

Given:
l = 100 yards
w = 20 yards

Solution:
put the numbers to the formula
a = l × w
a = 100 × 20
a = 2,000
The area of the field is 2,000 square yards

3 0

2 years ago

Read 2 more answers