Answer:
Step-by-step explanation:
Given that a basketball coach will select the members of a five-player team from among 9 players, including John and Peter.
Out of nine players five are chosen at random.
The team consists of John and Peter.
Hence we can sort 9 players as I group, John and Peter and II group 7 players.
Now the selection is 2 from I group and remaining 3 from II group.
Hence no of ways of selecting a team that includes both John and Peter=
=35
Total no of ways = 
=126
= 
=
Answer:
A = (x + 15)(x + 10) − 5
Step-by-step explanation:
(x+15)(x+10)-5=A would be a solution
To make this easier, let's assign x a value. Let's say 3.
(3+15)(3+10)-5=A
(18)(13)-5=A
234-5=A
A=229
Now with this, we put x in the answer choice and the answer that gives an area of 229 is correct.
A. A=(3+20)(3+10)+12=(23)(13)+12=299+12=311 <u>Answer A is wrong.</u>
B. A=(3+20)(3+10)-12=(23)(13)-12=299-12=287 <u>Answer B is wrong.</u>
C. A=(3+26)(3+15)=(29)(18)=522 <u>Answer C is wrong.</u>
D. A=(3+14)(3+8)=(17)(11)=187 <u>Answer D is wrong.</u>
It's either I'm wrong or the answer choices are wrong.
New answer choices!
A. A=(3+20)(3+11)
=(23)(14)=322 Answer A is wrong.
B. A=(3+15)(3+10)+5
=(18)(13)+5=234+5=239 Answer B is wrong.
C. A=(3+15)(3+10)−5
=(18)(13)-5=234-5=229 Answer C is correct.
D. A=(3+9)(3+10)=(12)(13)=156 <u>Answer D is wrong.</u>
Answer:
B
Step-by-step explanation:
if all sides are equal and there are 7 sides than each side has and equal opportunity to be landed on.
