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2 years ago

Can you please help me please

Mathematics

2 answers:

aalyn [17]2 years ago

6 0

Answer:

READ BELOW

Step-by-step explanation:

Hello! When the problem is asking for a sequence of number we MUST follow the same sequence, so our answers match up.

In the table, we can see that for the first-row x=2

Because we know that that x=2, for now, we have to plug in for x

When we plug in x for 2, we get the equation 5+4(2) =y We know that we MUST multiply first to get 8 then add 5 which gives us 13

SO y= 13 for the first column

Then we need to go down the table to do the same thing we did for the first row

We must change x to 4,8, and 10 by following the same steps

The equation stays the same but x changes to the number given

Our new equations are

y=5+4(4) Which results in 21

y=5+4(8) Which results in 37

y=5+4(10) Which results in 45

Alika [10]2 years ago

5 0

Answer:

2=13

4=21

8=37

10=45

Bc all you are doing is replacing the x with the # to the left.

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A fast-food restaurant sold 54 burgers with cheese. If the ratio of burgers sold with cheese compared to without cheese was 9: 5

alex41 [277]

Answer:

Step-by-step explanation:

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4 0

3 years ago

A new test to detect TB has been designed. It is estimated that 88% of people taking this test have the disease. The test detect

Elodia [21]

Answer:

Correct option: (a) 0.1452

Step-by-step explanation:

The new test designed for detecting TB is being analysed.

Denote the events as follows:

<em>D</em> = a person has the disease

<em>X</em> = the test is positive.

The information provided is:

$P(D)=0.88\\P(X|D)=0.97\\P(X^{c}|D^{c})=0.99$

Compute the probability that a person does not have the disease as follows:

$P(D^{c})=1-P(D)=1-0.88=0.12$

The probability of a person not having the disease is 0.12.

Compute the probability that a randomly selected person is tested negative but does have the disease as follows:

$P(X^{c}\cap D)=P(X^{c}|D)P(D)\\=[1-P(X|D)]\times P(D)\\=[1-0.97]\times 0.88\\=0.03\times 0.88\\=0.0264$

Compute the probability that a randomly selected person is tested negative but does not have the disease as follows:

$P(X^{c}\cap D^{c})=P(X^{c}|D^{c})P(D^{c})\\=[1-P(X|D)]\times{1- P(D)]\\=0.99\times 0.12\\=0.1188$

Compute the probability that a randomly selected person is tested negative as follows:

$P(X^{c})=P(X^{c}\cap D)+P(X^{c}\cap D^{c})$

$=0.0264+0.1188\\=0.1452$

Thus, the probability of the test indicating that the person does not have the disease is 0.1452.

4 0

3 years ago

Jane's salary is increased by 2% to $30396. How much was her salary before the rise?

harina [27]

_award brainliest if helped!

so 102% = 30396
100% (original) = 30396/102*100 =29800

Her salary was $29800 before the rise

6 0

3 years ago

Read 2 more answers

I'll give you brainlies if you help me on this!

ryzh [129]

Answer:

5/4 ounces.

Step-by-step explanation:

There are 4 marks. So 1/4 is the smallest one. There are 5 of them. 5x1/4 is 5/4 or 1 1/4

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2 years ago

Read 2 more answers

Please solve this I'll give a good review and comment ty ^^ I also will give brainly if somebody else answers

IRISSAK [1]

Answer:

3. B

4. D

5. A

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6 0

3 years ago