Graph 1: Domain = 2 <= x < 12
Graph 1: Range = {2,4}
Graph 2: Domain = 3 <= x <= 10
Graph 2: Range = -6 <= y <= 4
Graph 3: Domain = 4 < x < 11
Graph 4: Range = -6 <= y < 2
Answer:
12m
Step-by-step explanation
If the height of the ball after x seconds be modelled by the equation
h(x)=−(x−2)² +16
The height of the ball at the time it is thrown will be the height at the initial time. At that point that it is initially thrown the time is 0seconds i.e x = 0
To get the height at t x = 0seconds, we will substitute x = 0 into the modeled function to have;
h(0) = -(-0-2)²+16.
h(0) = -(-2)²+16
h(0) = -4+16
h(0) = 12
The height of the ball at the time the ball is thrown is 12m
Step 1: All angles in a triangle must add up to 180! Therefore, in the upper triangle, add up the two you know 85+35=120 so the missing angle is 60.
Step 2: Bottom triangle. Your new angle above (60) is the pair of the opposite angle - so it too is 60. So now you know 2 of the 3 angles: 60+64=124 Subtract that from 180 and you get 56...which is the answer for ?
The answer is the fraction is 66/100 or simplified, 2/3<span />
The answers are as follows:
Box 1) D
Box 2) .02D
Box 3) D + .02D
