Find the slope of the line passing through (5,2) and (8,3).

For a class activity, your group has been assigned the task of generating a quiz question that requires use of the formula for c

soldier1979 [14.2K]

Answer: P(A and B) is greater than P(A)

P(A and B) should be smaller than P(A).

Step-by-step explanation:

Given : P(A and B) = 0.40

P(A) = 0.20

Using the given formula of the conditional probability will be

$P(B|A)=\dfrac{\text{P(A and B)}}{P(A)}\\\\=\dfrac{0.40}{0.20}=2$

But we know that the probability of any event cannot be more than 1.

Also, the probability of the intersection must be less than the probability of individual event.

Thus , in the given question P(A and B) must be smaller than P(A).

3 0

2 years ago

In a circle with a radius of 12.6 ft, an arc is intercepted by a central angle of 2π/7 radians.

Hitman42 [59]

11.30
just convert it :)

6 0

2 years ago

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The rainfall amount last year was 6 inches below normal. The rainfall this year was 13 inches more than last year. What is the d

Lostsunrise [7]

Answer:

7

Step-by-step explanation:

The term difference means to subtract. Therefore, 13in - 6in, is equal to 7 inches.

13-6=7

Hope this Helps!!!

6 0

3 years ago

A communications channel transmits the digits 0 and 1. However, due to static, the digit transmitted is incorrectly received wit

m_a_m_a [10]

Answer:

The probability that the message will be wrong when decoded is 0.05792

Step-by-step explanation:

Consider the provided information.

To reduce the chance or error, we transmit 00000 instead of 0 and 11111 instead of 1.

We have 5 bits, message will be corrupt if at least 3 bits are incorrect for the same block.

The digit transmitted is incorrectly received with probability p = 0.2

The probability of receiving a digit correctly is q = 1 - 0.2 = 0.8

We want the probability that the message will be wrong when decoded.

This can be written as:

$P(X\geq3) =P(X=3)+P(X=4)+P(X=5)\\P(X\geq3) =\frac{5!}{3!2!}(0.2)^3(0.8)^{2}+\frac{5!}{4!1!}(0.2)^4(0.8)^{1}+\frac{5!}{5!}(0.2)^5(0.8)^0\\P(X\geq3) =0.05792$

Hence, the probability that the message will be wrong when decoded is 0.05792

4 0

2 years ago

I'm solving systems and I don't understand how to do it pls helpp

kaheart [24]

Answer:

Use the process of elimination. I'll only do one example since you have 4.

Step-by-step explanation:

Let's do the first question.

2x-3y=-11

2x+y=9

Our goal here is to be left with one variable to solve, this way we can use the answer for that variable to find the other. A.K.A only find X to plug into the equation to find Y. To do this, we'll use the process of elimination, in which we need to cancel out a variable.

X seems the easiest here. To cancel 2 (in the top equation), you need to have a -2. And that -2 needs to be the x coefficient in the 2nd equation, in order for us to "cancel" it out. To get -2, you multiply 2 by -1.

-1(2x+y)= -1(9)

Note that whatever you do to one side, you need to do it to both sides! Hence, why I also multiplied 9 by -1. You should now be left with:

-2x -y = -9

Now, we cancel out the positive 2 and -2 from both equations by adding the two equations.

2x-3y= 11

+

-2x-y=-9

X cancels out, so we're left with -4y=-20. Solve for Y, which is 5.

-4y=-20

y=5

Now that you have the Y value, plug it into any of the two equations to find your X value.

2x-3y=11

2x-3(5)=11

2x-15=11

2x=26

x=13

And voilah! Our Y value is 5, and our X value is 13.

It's pretty simple once you understand what's going on. All that we did was to cancel out one variable (either X or Y) in the two equations so that we're left with only one variable to solve. If we cancel out X, we only need to solve for Y. You do this by manipulating one of the two equations (doesn't matter which one). Once you find either X or Y, all you need to is to plug it into one of the original equations. Then, you'll have both X and Y.

And that my friend, is the process of elimination. Good luck!

8 0

2 years ago

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