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lianna [129]
3 years ago
6

Another middle schooler (Swimmer 2) swims 24 laps in 20 minutes, what is the unit rate?

Mathematics
1 answer:
prohojiy [21]3 years ago
6 0

Answer:

1.2 laps per minute

Step-by-step explanation:

divide laps/minutes.

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Can someone explain how to do this and add the formula please
lisabon 2012 [21]

Answer:

5 is 35 and 6 is 50

Step-by-step explanation:

To solve 5, you need to know how many degrees is the line, which is 180 because lines are 180 degrees. You then subtract 110 from 180 which equals to 70. What you have left now is 2k. A number times 2 will equal to 70, so k=35.

For 6, if you ever see two lines intersecting each other, it means that it is 360 degrees. We already have one angle, which is 120. The other angle is d+70 degrees, and any angle that is reflecting the other angle will have the same value. So, d equals 50

(sorry if you still can't understand it I'm not good at English

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3 years ago
Brad buys two packages of mushrooms
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and he goes home and plants them and they grow

Step-by-step explanation:

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4 years ago
A ​$300 suit is marked down by ​%20. Find the sale price
avanturin [10]

Answer:

1499

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(Decimal: 299.8)

Step-by-step explanation: =

300

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20

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300

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7 0
3 years ago
Read 2 more answers
Write a definite integral that represents the area of the region. (Do not evaluate the integral.) y1 = x2 + 2x + 3 y2 = 2x + 12F
Svet_ta [14]

Answer:

A = \int\limits^3__-3}{9}-{x^{2}} \, dx = 36

Step-by-step explanation:

The equations are:

y = x^{2} + 2x + 3

y = 2x + 12

The two graphs intersect when:

x^{2} + 2x + 3 = 2x + 12

x^{2} = 0

x_{1}  = 3\\x_{2}  = -3

To find the area under the curve for the first equation:

A_{1} = \int\limits^3__-3}{x^{2} + 2x + 3} \, dx

To find the area under the curve for the second equation:

A_{2} = \int\limits^3__-3}{2x + 12} \, dx

To find the total area:

A = A_{2} -A_{1} = \int\limits^3__-3}{2x + 12} \, dx -\int\limits^3__-3}{x^{2} + 2x + 3} \, dx

Simplifying the equation:

A = \int\limits^3__-3}{2x + 12}-({x^{2} + 2x + 3}) \, dx = \int\limits^3__-3}{9}-{x^{2}} \, dx

Note: The reason the area is equal to the area two minus area one is that the line, area 2, is above the region of interest (see image).  

3 0
3 years ago
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