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gregori [183]
2 years ago
12

Find the ordered pair of both 4x-3y=6 and 6x + y =42

Mathematics
1 answer:
WINSTONCH [101]2 years ago
7 0

Answer:

(-60/11,111/11)

Step-by-step explanation:

Solving simultaneously, 4x - 3y=6

-3(6x + y=42)

then it becomes, 4x - 3y=6

-18x - 3y= 126 subtracting the two equations,

22x= -120, x= -60/11 and y = 111/11

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Evaluate -x + 2.7 for x =0.9
DiKsa [7]
Plug in 0.9 for x

-(x) + 2.7

- (0.9) + 2.7

simplify

2.7 - 0.9 = 1.8

1.8 is your answer

hope this helps
3 0
3 years ago
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What is the answer to 19+x/2=4?
salantis [7]
19+x/2=4
multiply 2 on both sides
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subtract 19 on each side
x=8-19
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8 0
3 years ago
What is the value of y?​
romanna [79]

Answer:

60

Step-by-step explanation:

y+y+60=180

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3 years ago
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Christian is throwing a pizza party . he has 1 1/3pounds of cheese available and he needs 1/2 pounds of cheese to make each pizz
Ivanshal [37]

Answer:

2

Step-by-step explanation:

3 0
3 years ago
A boat on the ocean is 2 mi from the nearest point on a straight? shoreline; that point is 15 mi from a restaurant on the shore.
Sladkaya [172]

Answer:

a) x  =  0,70 miles

T  =  1/2* (√4 + x²)  +( 15 - x )/3   Objective Function to minimize

b) V(min)  = 2.59 m/hr

Step-by-step explanation:

Let assume the boat is in Point A,  she lands in point B, and R  is the restaurant

Let call  x distance between the point O in  which perpendicular line from the boat get to shoreline, and the point were she land.

We know  distance is

d = v*t       ⇒  t = d/v

She rows at 2 miles/hr  and walk at 3 miles /hr

According to that she takes

c (hypotenuse) of right triangle  AOB/ 2 rowing

and  15 - x /3  walking

Total time is:

T  =  c/2  + ( 15-x )/3          c =√(2)² + x²     ⇒  T = [√(2)² + x²  ] /2  +  ( 15-x )/3  

T  =  1/2* (√4 + x²)  +( 15 - x )/3   (1)

And that is  the Objective function to minimize

a) Taking derivatives on both sides of the equation we get

T´(t)  =  x /( √4 + x²)  - 1/3    ⇒   T´(t)  = 0     x /( √4 + x²)  - 1/3 = 0

3*x - √( √4 + x²) = 0     ⇒  3*x  =  √( √4 + x²)

Squaring both sides

9x²  =  4 + x²     ⇒  8x²  = 4       x² = 1/2      x  =  0,70 miles

If we plug this value in the Objective function we will get the minimum time

1/2* (√4 + x²)  +( 15 - x )/3    ⇒ [√ 4  + 0,5] /2 +  14,3/3 = T (min)

T(min)  =  1.06 + 4.77  = 5.83 hr

Distance L (hypotenuse of right triangle AOR)

L = √(2)²  + (15)²   L  = 15,13 miles

And that distance have to be traveled at least in 5.83 hr rowing

Then  as  v = d/t      V(min)  =  15.13/ 5.83   ⇒    V(min)  = 2.59 m/hr

6 0
3 years ago
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