7. Easiest method is substitution. Since y=x/2, then:
2x+3(x/2)=28
8.Substituting again, we get:
3x-6x=6
-3x=6
x=-2
(-2,6)
☺☺☺☺
Given 2 points A(a,b) and M(k,l), the distance between them is found by the formula:
Let (k, l)=(2, 3), substituting in the above formula:
check each of the pairs given:
for (a, b)=(14, 15):
for (a, b)=(2, -9):
for (a, b)=(-2, -3):
for (a, b)=(-9, 2):
Answer: (2, -9)
No 1 1/4 is greater than 3/4
Answer: n>5
Step-by-step explanation:
We are given:
the center of the rink at the origin.
A skating path (Susan): y = 6x - x^2 - 5
Starting point of Luke = (10, -21)
Path (Luke) = quadratic eq'n with vertex at (8, -9)
Radius = 35 meters
The solution that best interprets the path of the skaters is to substitute Luke's starting point to Susan's path or set-up a quadratic equation with vertex of (8,-9) and then equate to Susan's path to solve for their intersection.