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Llana [10]
3 years ago
13

Susan's math teacher assigned x homework problems on Monday. On Tuesday, she assigned 15 more problems. Over the two

Mathematics
2 answers:
Radda [10]3 years ago
7 0
The answer is C because need to add 15 to Monday to get the answer which is 24
Romashka [77]3 years ago
5 0

Answer:

C

Step-by-step explanation:

We know that there were 24 questions in the 2 days

And we know that tuesday had 15 more question.

That means Monday had "x questions" + the 15 on tuesday to get 24 in total.

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Pls answer i give brainly!!!
vfiekz [6]

Answer:

A. Michael

He sold 2.

b. He sold 7 more.

c. 4 agents

3 0
3 years ago
Read 2 more answers
Correct answe please reward brainliest!!!!!
dedylja [7]

Answer:

The answer is B

Step-by-step explanation:

Mean= 3

yell at me if im not right lol

4 0
3 years ago
What is the equation of the line that passes through the point (-4,-2)(−4,−2) and has a slope of -\frac{1}{2}− 2 1 ​ ?
harkovskaia [24]

Answer:

Question not clear. I cant see the value for slope.

Step-by-step explanation:

5 0
3 years ago
Please help me if u do ill give to the best brainliest :)
shepuryov [24]

Step-by-step explanation:

t in 1200m:

t =  \frac{4500}{x}  \\ x = 1200 \\ t = 4500 \div 1200 = 3.75

t in 3750:

t =  \frac{4500}{x}  \\ x = 3750 \\ t = 4000  \div 3750 = 0.12

difference is:

3.75-0.12 = 3.63

4 0
3 years ago
A recent survey of students at John Tukey High School revealed that
RoseWind [281]

Answer:

0.5234 = 52.34% probability that at least three of these students are in favor of the proposal to change the dress code.

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they are in favor, or they are not. Students are independent. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

18% of the students are in favor of changing the dress code.

This means that p = 0.18

You randomly select 15 students

This means that n = 15

What is the probability that at least three of these students are in favor of the proposal to change the dress code?

This is

P(X \geq 3) = 1 - P(X < 3)

In which

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{15,0}.(0.18)^{0}.(0.82)^{15} = 0.051

P(X = 1) = C_{15,1}.(0.18)^{1}.(0.82)^{14} = 0.1678

P(X = 2) = C_{15,2}.(0.18)^{2}.(0.82)^{13} = 0.2578

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.051 + 0.1678 + 0.2578 = 0.4766

P(X \geq 3) = 1 - P(X < 3) = 1 - 0.4766 = 0.5234

0.5234 = 52.34% probability that at least three of these students are in favor of the proposal to change the dress code.

8 0
3 years ago
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