√49z²
= √(7z)². [ here, Square cancles sq. root]
= 7z
May be Helpful.
Thank you!
Answer:
Step-by-step explanation:
Given the function :
y=x³ - 3x² - 9x + 2. The largest and smallest values of the function at interval [-2, 4]
We substitute x values in the interval (-2 to 4) into the equation and solve for y
At x = - 2
y = (-2)³ - 3(-2)² - 9(-2) + 2 = 0
At x = - 1
y = (-1)³ - 3(-1)² - 9(-1) + 2 = 7
At x = 0
y = (-0)³ - 3(-0)² - 9(-0) + 2 = 2
At x = 1
y = (1)³ - 3(1)² - 9(1) + 2 = - 9
At x = 2
y = (2)³ - 3(2)² - 9(2) + 2 = - 20
At x = 3
y = (3)³ - 3(3)² - 9(3) + 2 = - 25
At x = 4
y = (4)³ - 3(4)² - 9(4) + 2 = - 18
Function is greatest at
The first answer is “B” and the second one is “D”. Attached below is my work.
I hoped this helped!! ^w^
To isolate the variable multiply both sides by 5.
-3 = x/5
-3*5 = x/5 * 5
-15 = x
Answer:
144(3/4)^1-n
Step-by-step explanation:
This is a geometric sequence, so if you divide 192 by 144 you will find that the common ratio r is 4/3. This would make the equation an=144(4/3)^n-1. However, that's not one of the options. If you plug in some numbers, you can see that 3/4 (the reciprocal of 4/3) can work as well if it's 3/4^1-n. 4/3^-1=3/4 and n-1(-1)=1-n