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3 years ago

A right triangle has side lengths 8 ,15 , 17 and as shown below.

Mathematics

1 answer:

raketka [301]3 years ago

6 0

Answer:

Step-by-step explanation:

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If 7 lbs of tomatoes cost £10.50 how much will 3 pounds of tomato cost??plz help Asap

STALIN [3.7K]

Answer:

4.5

Step-by-step explanation:

10.50 divided by 7 = 1.50

1.50 times 3 = 4.5

5 0

3 years ago

Help idk the answer

BartSMP [9]

6(5 - 3x) = 7(10 - 2x)

30 - 18x = 70 - 14x

-18x = 40 - 14x

-4x = 40

x = -10

5 0

3 years ago

Read 2 more answers

Craig measured a length as 0.034 millimeters. What is the margin of error? 0.03 mm to 0.04 mm 0.033 mm to 0.034 mm 0.0335 mm to

WARRIOR [948]

C. 0.0335 mm to 0.0345 mm

Step-by-step explanation:

The least significant digit of Craig's measurement is in the 0.001 mm place. The error in the measurement is presumed to fall within half that value either side of Craig's measurement. So, the actual value is expected to be in the range ...

0.034 - 0.0005 = 0.0335

0.034 + 0.0005 = 0.0345

The measurement is presumed to be in the range 0.0335 mm to 0.0345 mm.

8 0

3 years ago

**Offering a good bit of my points, please don't randomly type something. I really need help. Can someone answer these 3 questio

inysia [295]

Step-by-step explanation:

y =39x + 125

y = 15x + 499

y = 25000 - 2300x

7 0

3 years ago

Two of the steps in the derivation of the quadratic formula are shown below.

Svetllana [295]

The step 7 is a wrong step, because in the denominator 1 is written in place of 2.

<h3>What is a quadratic equation?</h3>

The quadratic equation is given as ax² + bx + c = 0. Then the degree of the equation will be 2. Then we have

Two of the steps in the derivation of the quadratic formula are shown below.

The equation is given below.

$\rm \dfrac{b^2 - 4ac}{4a^2} = \left (x + \dfrac{b}{2a} \right )^2$

Then the above equation can be written as

$\rm \pm \sqrt{ \dfrac{b^2 - 4ac}{4a^2}} = \left (x + \dfrac{b}{2a} \right )\\\\\\x = \dfrac{-b}{2a} \pm \sqrt{ \dfrac{b^2 - 4ac}{4a^2}}\\\\\\x = \dfrac{-b}{2a} \pm \dfrac{\sqrt{ b^2 - 4ac}}{2a}\\\\\\x = \dfrac{-b \pm \sqrt{ b^2 - 4ac}}{2a}$

The step 7 is a wrong step, because in the denominator 1 is written in place of 2.

More about the quadratic equation link is given below.

brainly.com/question/2263981

#SPJ1

7 0

2 years ago